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This deck focuses on Introduction To Equilibrium, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Study Introduction To Equilibrium in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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What is the effect of changing concentration on the equilibrium constant?
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No effect; K is constant at a given temperature. Only temperature affects K; concentration changes shift position only.
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This deck focuses on Introduction To Equilibrium, giving you a quick way to review the definitions, rules, and examples that matter most for AP Chemistry.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: No effect; K is constant at a given temperature. Only temperature affects K; concentration changes shift position only.
Answer: Kp=Kc(RT)Δn, where Δn is moles of gas change. Converts between concentration and pressure equilibrium constants.
Answer: The reaction is at equilibrium. Current reaction quotient equals equilibrium constant; no net change occurs.
Answer: Kc for reversed reaction is Kc1 of the forward reaction. Reversing a reaction inverts its equilibrium constant value.
Answer: K changes; depends on reaction's endothermic or exothermic nature. Temperature is the only factor that changes the equilibrium constant value.
Answer: K changes; depends on reaction's endothermic or exothermic nature. Temperature is the only factor that changes the equilibrium constant value.
Answer: No effect; not included in K expressions. Pure phases have constant activity and don't appear in expressions.
Answer: If Q<K, shifts right; if Q>K, shifts left. Compares current state to equilibrium to predict reaction direction.
Answer: Equilibrium position changes with temperature. Different temperatures give different K values for the same reaction.
Answer: They become exponents for concentration terms in K expressions. Stoichiometric coefficients become powers in the equilibrium constant expression.
Answer: Shifts towards the product side. Higher temperature favors the endothermic direction (forward reaction).
Answer: Reactants are favored at equilibrium. Smaller K means equilibrium lies toward the reactant side.
Answer: No effect on the position of equilibrium. Inert gases don't participate in the reaction or affect concentrations.
Answer: Unitless; derived from concentration terms. Concentration units cancel out in the ratio of products to reactants.
Answer: Significant formation of reactants at equilibrium. Small K indicates equilibrium strongly favors reactant formation.
Answer: Shifts towards the product side. Higher temperature favors the endothermic direction (forward reaction).
Answer: Reactants and products form at the same rate. Concentrations remain constant while reactions continue in both directions.
Answer: Increases rate without affecting equilibrium position. Catalyst speeds both directions equally, reaching equilibrium faster.
Answer: Equilibrium where all reactants and products are in the same phase. All species exist in one phase (all gas, liquid, or aqueous).
Answer: Kp=Kc(RT)Δn, where Δn is moles of gas change. Converts between concentration and pressure equilibrium constants.
Answer: A catalyst does not affect the position of equilibrium. Catalysts speed up both forward and reverse reactions equally.
Answer: Significant formation of products at equilibrium. Large K indicates equilibrium strongly favors product formation.
Answer: K=[reactants][products]. Products in numerator, reactants in denominator, each raised to their coefficients.
Answer: The ratio of product and reactant concentrations at any point in time. Same form as K but uses current concentrations, not equilibrium values.
Answer: Shifts towards the side with more moles of gas. Lower pressure favors the side with more gas molecules to increase volume.
Answer: Significant formation of reactants at equilibrium. Small K indicates equilibrium strongly favors reactant formation.
Answer: They become exponents for concentration terms in K expressions. Stoichiometric coefficients become powers in the equilibrium constant expression.
Answer: The system is at equilibrium. No driving force exists for net reaction in either direction.
Answer: Equilibrium with reactants and products in different phases. Species exist in multiple phases (solid, liquid, gas, aqueous combinations).
Answer: The state where the rates of forward and reverse reactions are equal. Forward and reverse reaction rates balance, maintaining constant concentrations.
Answer: Shifts towards the product side. System shifts to consume the added reactant by forming more products.
Answer: K=[reactants][products]. Products in numerator, reactants in denominator, each raised to their coefficients.
Answer: The system is at equilibrium. No driving force exists for net reaction in either direction.
Answer: Kc=[A]a[B]b[C]c[D]d. Products raised to their coefficients divided by reactants raised to their coefficients.
Answer: If Q<K, shifts right; if Q>K, shifts left. Compares current state to equilibrium to predict reaction direction.
Answer: Shifts towards the reactant side. System shifts to consume the added product by forming more reactants.
Answer: Shifts towards the reactant side. System shifts to consume the added product by forming more reactants.
Answer: Unitless; derived from partial pressure terms. Pressure units cancel out in the ratio of products to reactants.
Answer: Reversible reactions. Irreversible reactions proceed to completion; only reversible ones reach equilibrium.
Answer: Determines if the reaction shifts left or right to reach equilibrium. Comparison of Q and K predicts which direction favors equilibrium.
Answer: Shifts towards the product side. System shifts to consume the added reactant by forming more products.
Answer: K is raised to the power of that factor. Multiplying equation by n raises the equilibrium constant to power n.
Answer: Shifts towards the product side. Lower temperature favors the exothermic direction (forward reaction).
Answer: The ratio of product concentrations to reactant concentrations at equilibrium. Higher K means more products; lower K means more reactants at equilibrium.
Answer: Products are favored at equilibrium. Larger K means equilibrium lies toward the product side.
Answer: Reactants and products form at the same rate. Concentrations remain constant while reactions continue in both directions.
Answer: No effect; K is constant at a given temperature. Only temperature affects K; concentration changes shift position only.
Answer: Temperature; not concentration or pressure. Pressure and concentration changes shift position but don't change K.
Answer: Shifts towards the side with fewer moles of gas. Pressure increase favors the side with less gas molecules to reduce volume.
Answer: Systems at equilibrium react to disturbances by shifting to counteract the change. Equilibrium shifts to oppose external changes and restore balance.
Answer: Significant formation of products at equilibrium. Large K indicates equilibrium strongly favors product formation.
Answer: Kp=PAaPBbPCcPDd. Uses partial pressures instead of concentrations in the equilibrium expression.
Answer: Systems at equilibrium react to disturbances by shifting to counteract the change. Equilibrium shifts to oppose external changes and restore balance.