Volume

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Pre-Algebra › Volume

Questions 1 - 10

1

Michelle plays softball for her high school. She is the only pitcher on the team. She is the only player that is guaranteed to touch the ball on every play. The problem is, her hands are not big enough to get a grip on the ball because the ball is too big. What is the volume of the softball that has a diameter of 6 inches?

$36 \pi inches^3$

$288\pi inches^3$

$36\pi inches^2$

$288\pi inches^2$

$48\pi inches^3$

Explanation

The formula to find the volume of a sphere is $\frac{4}{3} * \pi * r^3$

Find the radius of the softball and substitute that in place of r.

Answer will be left in pi format.

$36\pi inches^3$

2

Michelle plays softball for her high school. She is the only pitcher on the team. She is the only player that is guaranteed to touch the ball on every play. The problem is, her hands are not big enough to get a grip on the ball because the ball is too big. What is the volume of the softball that has a diameter of 6 inches?

$36 \pi inches^3$

$288\pi inches^3$

$36\pi inches^2$

$288\pi inches^2$

$48\pi inches^3$

Explanation

The formula to find the volume of a sphere is $\frac{4}{3} * \pi * r^3$

Find the radius of the softball and substitute that in place of r.

Answer will be left in pi format.

$36\pi inches^3$

3

A matchbox has a length of 10 inches, width of 2 inches and height of 1 inch. What is the volume of the matchbox?

Explanation

To find the volume of a rectangular solid you must multiply the length, width, and height together.

Volume is in units cubed.

4

A matchbox has a length of 10 inches, width of 2 inches and height of 1 inch. What is the volume of the matchbox?

Explanation

To find the volume of a rectangular solid you must multiply the length, width, and height together.

Volume is in units cubed.

5

The volume of a cube is . What is the length of an edge of the cube?

Explanation

Let be the length of an edge of the cube. The volume of a cube can be determined by the equation:

$\sqrt[3]{x^3}=\sqrt[3]{64}$

6

The volume of a cube is . What is the length of an edge of the cube?

Explanation

Let be the length of an edge of the cube. The volume of a cube can be determined by the equation:

$\sqrt[3]{x^3}=\sqrt[3]{64}$

7

What is the volume of a cone with a radius of 5 and a height of 6?

$50\pi$

$125\pi$

$150\pi$

$450\pi$

$10\pi$

Explanation

Write the formula to find the volume of a cone.

$V=\frac{1}{3} \pi r^2 h$

Substitute the dimensions and solve.

$V=\frac{1}{3} \pi (5)^2 (6) = \pi (5)^2 (2) = 50 \pi$

8

Find the volume of a pyramid with a length of 2, width of 6, and a height of 9.

Explanation

Write the formula for the volume of a pyramid.

$V=\frac{1}{3} (\textup{ Length} \times\textup{ Width} \times\textup{ Height})$

Substitute the given length, width, and height.

$V=\frac{1}{3} (2\times6\times9)$

Rewrite the inside the parentheses as a factor of .

$V=\frac{1}{3} (2\times (3 \times 2)\times9)$

Cancel the fraction with the three and multiply the terms to get the volume.

$V=2\times 2\times 9 = 36$

9

What is the volume of a cone with a radius of 5 and a height of 6?

$50\pi$

$125\pi$

$150\pi$

$450\pi$

$10\pi$

Explanation

Write the formula to find the volume of a cone.

$V=\frac{1}{3} \pi r^2 h$

Substitute the dimensions and solve.

$V=\frac{1}{3} \pi (5)^2 (6) = \pi (5)^2 (2) = 50 \pi$

10

Find the volume of a pyramid with a length of 2, width of 6, and a height of 9.

Explanation

Write the formula for the volume of a pyramid.

$V=\frac{1}{3} (\textup{ Length} \times\textup{ Width} \times\textup{ Height})$

Substitute the given length, width, and height.

$V=\frac{1}{3} (2\times6\times9)$

Rewrite the inside the parentheses as a factor of .

$V=\frac{1}{3} (2\times (3 \times 2)\times9)$

Cancel the fraction with the three and multiply the terms to get the volume.

$V=2\times 2\times 9 = 36$

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