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Pre-Algebra : Algebraic Equations

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11 Diagnostic Tests 177 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #24 : One Step Equations With Integers

Solve for $\displaystyle y$.

y+7=2 $\displaystyle y+7=2$

Possible Answers:

y=9 $\displaystyle y=9$

y=14 $\displaystyle y=14$

y=0 $\displaystyle y=0$

y=-5 $\displaystyle y=-5$

y=7 $\displaystyle y=7$

Correct answer:

y=-5 $\displaystyle y=-5$

Explanation:

To get y by itself, you must subtract 7 from both sides

$\displaystyle (y+7)-7=2-7$

which simplifies to

y=-5 $\displaystyle y=-5$

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Example Question #23 : One Step Equations With Integers

Solve for $\displaystyle x$.

x-4=-2 $\displaystyle x-4=-2$

Possible Answers:

x=-8 $\displaystyle x=-8$

x=0 $\displaystyle x=0$

x=2 $\displaystyle x=2$

x=4 $\displaystyle x=4$

x=-6 $\displaystyle x=-6$

Correct answer:

x=2 $\displaystyle x=2$

Explanation:

To get x by itself, you must add 4 to both sides of the equation

$\displaystyle x-4+4=-2+4$

which simplifies to

x=2 $\displaystyle x=2$

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Example Question #706 : Grade 6

Solve for $\displaystyle y$.

$\frac{y}{3}=3$ $\displaystyle \frac{y}{3}=3$

Possible Answers:

y=6 $\displaystyle y=6$

y=10 $\displaystyle y=10$

y=27 $\displaystyle y=27$

y=3 $\displaystyle y=3$

y=9 $\displaystyle y=9$

Correct answer:

y=9 $\displaystyle y=9$

Explanation:

To get y by itself, you must multiply both sides of the equation by 3

$\frac{y}{3}\times3=3\times3$ $\displaystyle \frac{y}{3}\times3=3\times3$

which simplifies to

y=9 $\displaystyle y=9$

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Example Question #29 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Solve for $\displaystyle z$.

z+11=11 $\displaystyle z+11=11$

Possible Answers:

z=3 $\displaystyle z=3$

z=22 $\displaystyle z=22$

z=121 $\displaystyle z=121$

z=0 $\displaystyle z=0$

z=1 $\displaystyle z=1$

Correct answer:

z=0 $\displaystyle z=0$

Explanation:

To get z by itself, you must subtract 11 from both sides

$\displaystyle z+11-11=11-11$

which simplifies to

z=0 $\displaystyle z=0$

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Example Question #25 : One Step Equations With Integers

Solve for $\displaystyle y$.

y-7=10 $\displaystyle y-7=10$

Possible Answers:

y=0 $\displaystyle y=0$

y=3 $\displaystyle y=3$

y=17 $\displaystyle y=17$

y=-3 $\displaystyle y=-3$

y=2 $\displaystyle y=2$

Correct answer:

y=17 $\displaystyle y=17$

Explanation:

To get y by itself, you must add 7 to both sides of the equation

$\displaystyle y-7+7=10+7$

which simplifies to

y=17 $\displaystyle y=17$

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Example Question #31 : One Step Equations

-x=4-2x $\displaystyle -x=4-2x$

Solve for $\displaystyle x$.

Possible Answers:

$\displaystyle 4$

$\displaystyle 3$

$\displaystyle 0$

$\displaystyle 2$

$\displaystyle -4$

Correct answer:

$\displaystyle 4$

Explanation:

Add 2x to each side to get all variables on one side:

-x=4-2x $\displaystyle -x=4-2x$

+2x +2x $\displaystyle +2x +2x$

x=4 $\displaystyle x=4$

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Example Question #211 : Algebraic Equations

32s=128 $\displaystyle 32s=128$

Solve for $\displaystyle s$.

Possible Answers:

$\displaystyle 4$

$\displaystyle 0$

$\displaystyle 3$

$\displaystyle 1$

$\displaystyle 7$

Correct answer:

$\displaystyle 4$

Explanation:

To isolate the variable "s" from the expression 32s, divide both sides of the equation by 32. 128/32=4, so s=4

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Example Question #711 : Grade 6

$\displaystyle -3652+y=1372$

Solve for $\displaystyle y$.

Possible Answers:

2280 $\displaystyle 2280$

5024 $\displaystyle 5024$

$\displaystyle -5024$

$\displaystyle 15$

$\displaystyle -2280$

Correct answer:

5024 $\displaystyle 5024$

Explanation:

Add 3625 to each side to isolate y. This gives you the answer 5024

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Example Question #712 : Grade 6

Solve: $\frac{x}{10} = 100$ $\displaystyle \frac{x}{10} = 100$

Possible Answers:

1000 $\displaystyle 1000$

$\displaystyle 90$

$\displaystyle 10$

$\frac{1}{10}$ $\displaystyle \frac{1}{10}$

110 $\displaystyle 110$

Correct answer:

1000 $\displaystyle 1000$

Explanation:

To solve for $\displaystyle x$, multiply ten on both sides of the equation to eliminate the denominator.

$\frac{x}{10} \times 10= 100\times 10$ $\displaystyle \frac{x}{10} \times 10= 100\times 10$

x=1000 $\displaystyle x=1000$

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Example Question #713 : Grade 6

solve for $\displaystyle x$:

x+15=7 $\displaystyle x+15=7$

Possible Answers:

x=-8 $\displaystyle x=-8$

x=22 $\displaystyle x=22$

x=8 $\displaystyle x=8$

x=-22 $\displaystyle x=-22$

None of the other answers.

Correct answer:

x=-8 $\displaystyle x=-8$

Explanation:

To solve for x you simply isolate it on one side of the equation. To do this, apply the opposite operations to manipulate the equation.

x+15=7 $\displaystyle x+15=7$

Subtract 15 from both sides:

$x{\color{Red} +15-15}=7-15$ $\displaystyle x{\color{Red} +15-15}=7-15$

The red terms canceled.

x=7-15 $\displaystyle x=7-15$

We just subtract as normal on the right side.

x=-8 $\displaystyle x=-8$

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Pre-Algebra : Algebraic Equations

Study concepts, example questions & explanations for Pre-Algebra

All Pre-Algebra Resources

Example Questions

Example Question #24 : One Step Equations With Integers

Example Question #23 : One Step Equations With Integers

Example Question #706 : Grade 6

Example Question #29 : Evaluate Expressions: Ccss.Math.Content.6.Ee.A.2c

Example Question #25 : One Step Equations With Integers

Example Question #31 : One Step Equations

Example Question #211 : Algebraic Equations

Example Question #711 : Grade 6

Example Question #712 : Grade 6

Example Question #713 : Grade 6

All Pre-Algebra Resources

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