The formula to find the area of a triangle is

\(\displaystyle A = \frac{1}{2} \cdot b \cdot h\)

where b is the base and h is the height.  We know the base of our triangle is 4cm.  We know the height is two times the base, so the height is 8cm.  Now, we substitute

\(\displaystyle A = \frac{1}{2} \cdot 4\text{cm} \cdot 8\text{cm}\)

\(\displaystyle A = 2\text{cm} \cdot 8\text{cm}\)

\(\displaystyle A = 16\text{cm}^2\)

Therefore, the area of the triangle is \(\displaystyle 16\text{cm}^2\).

To find the area of a triangle, multiply the base by the height, and divide by two.  The best answer is:

\(\displaystyle 18\) square inches

To find the area of a triangle, multiply the base by the height, and divide by two.  The best answer is:

\(\displaystyle 53.4\) square inches

To find the area of a triangle, multiply the base by the height, and divide by two.  The best answer is:

\(\displaystyle \frac{xy}{2}\) square inches

To find the area of a triangle, multiply the base by the height, and divide by two.  The best answer is:

\(\displaystyle 4t\) square inches

The formula for the area of a triangle is:

\(\displaystyle \frac{1}{2} * base * height\)

\(\displaystyle \frac{1}{2} * 14 * 22 = 154in ^2\)

To find the area of a triangle, use the formula \(\displaystyle \frac{1}{2}(b\times h)\)or \(\displaystyle \frac{b\times h}{2}\)

\(\displaystyle \frac{1}{2}\) \(\displaystyle (3x4)=\) 

\(\displaystyle \frac{1}{2}(12)=\)

\(\displaystyle 6\) square ft

or

\(\displaystyle \frac{(3x4)}{2}=\)

\(\displaystyle \frac{12}{2}=\)

\(\displaystyle 6\) square ft

To begin, we need to find the radius of the circle. The circumference of a circle is given as follows:

\(\displaystyle \small C = 2\pi r\),

where \(\displaystyle r\) is the radius.

Then, a circle with circumference \(\displaystyle 6\pi\) will have the following radius:

\(\displaystyle 6\pi = 2\pi r\)

\(\displaystyle \small \frac{6\pi}{2\pi}=\frac{2\pi r}{2\pi}\)

\(\displaystyle \small 3=r\)

Using the radius, we can now solve for the area:

\(\displaystyle \small A=\pi r^2\)

\(\displaystyle A=\pi(3)^2\)

\(\displaystyle \small A=9\pi\)

The area of the circle is \(\displaystyle \small 9\pi\).

If the diameter is 7, then the radius is half of 7, or 3.5.

Plug this value for the radius into the equation for the area of a circle:

\(\displaystyle A=r^2\pi=(3.5)^2\pi=12.25\pi\)

The orange region is a composite of two figures:

One is a rectangle measuring 20 by 10, which, subsequently, has area

\(\displaystyle 20 \cdot 10 = 200\).

The other is a semicircle with diameter 10, and, subsequently, radius 5. Its area is 

\(\displaystyle \frac{1}{2} \pi \cdot 5^{2} = \frac{25}{2} \pi\).

Add the areas:

\(\displaystyle A = 200 + \frac{25}{2} \pi\)