Recall the order of operations, PEMDAS, which stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.

From the concept of order of operations, we would evaluate terms in multiplication first since there are no parentheses or exponents.

\(\displaystyle 2-2\times 3+5 = 2-(2\times 3)+5\)

Once we multiply two and three together, add and subtract values starting from the left, working your way to the right.

\(\displaystyle 2-6+5 = 1\)

Recall the order of operations to solve this problem.

PEMDAS stands for the order in which to solve an expression. First do whatever is inside of parentheses, then apply the exponents. Next, perform the multiplication and division and lastly do any addition and subtraction from left to right.

Evalute this by first applying the order of operations.  

Multiply the second and the third terms first.

\(\displaystyle 10-(10\times 2)-2 = 10-20-2\)

Subtract.

\(\displaystyle 10-20-2=-12\)

Use the order of operations to solve. Evaluate the parentheses, exponents, multiplication, division, addition, and subtraction in chronological order.

This is known as PEMDAS.

\(\displaystyle \\4-(4\times7)+(12\div4) \\= 4-28+3\)

Solve by adding and subtracting the values from left to right.

\(\displaystyle 4-28+3 = -21\)

Evaluate this by order of operations.  Solve the parentheses first.

\(\displaystyle \frac{3}{2}-\frac{3}{2}(2-3) = \frac{3}{2}-\frac{3}{2}(-1)\)

Eliminate the parentheses by multiplying the fraction and the whole number.  Remember that multiplying two negative numbers will result in a positive number.

\(\displaystyle \frac{3}{2}-\frac{3}{2}(-1) = \frac{3}{2}+\frac{3}{2}\)

Add the two fractions.

\(\displaystyle \frac{3}{2}+\frac{3}{2}\)

The numerators can be added since the denominators are common.  The denominators will stay the same.

\(\displaystyle \frac{3}{2}+\frac{3}{2} = \frac{6}{2}\)

Divide six and two.  

\(\displaystyle \frac{6}{2}=3\)

The answer is \(\displaystyle 3\).

To complete a problem with order of operations, follow the acronym PEMDAS to remember the order of completion. PEMDAS stands for:

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction.

For this problem, we do the multiplication/division before addition/subtraction to get our final answer of 48:

\(\displaystyle 26+3\cdot4\div2+7\cdot5-19\)

\(\displaystyle 26+12\div2+35-19\)

\(\displaystyle 26+6+35-19\)

\(\displaystyle 32+35-19\)

\(\displaystyle 67-19=48\)

To complete a problem with order of operations, follow the acronym PEMDAS to remember the order of completion. PEMDAS stands for:

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction.

For this problem, we do multiplication before addition to get our final answer of 34:

\(\displaystyle 6\cdot4+3-6+13\)

\(\displaystyle 24+3-6+13\)

\(\displaystyle 27-6+13\)

\(\displaystyle 21+13=34\)

To solve this, we use the order of operations.  The order of operations is

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

We must solve the problem in the proper order, starting first with parentheses and ending with subtraction.  Using the order of operations, we get

Initial Problem:

\(\displaystyle 2(4+3) + 3^2 *7\)

Solve parentheses:

\(\displaystyle 2(7) + 3^2 *7\) 

Solve exponents:

\(\displaystyle 2(7) + 9 *7\)

Mulitply:

\(\displaystyle 14 + 63\)

Add:

\(\displaystyle 77\)

So the final solution is 77.

To complete a problem with order of operations, follow the acronym PEMDAS to remember the order of completion. PEMDAS stands for:

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction.

For this problem, we solve the exponent, then complete the division before doing the addition/subtraction to get our final answer of 13:

\(\displaystyle 2^{2}-3+15-6\div2\)

\(\displaystyle 4-3+15-6\div2\)

\(\displaystyle 4-3+15-3\)

\(\displaystyle 1+15-3\)

\(\displaystyle 16-3=13\)

To complete a problem with order of operations, follow the acronym PEMDAS to remember the order of completion. PEMDAS stands for:

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction.

For this problem, we do the multiplication before the addition/subtraction to get our final answer of 14:

\(\displaystyle 15-6+3\cdot4-7\)

\(\displaystyle 15-6+12-7\)

\(\displaystyle 9+12-7\)

\(\displaystyle 21-7=14\)

To complete a problem with order of operations, follow the acronym PEMDAS to remember the order of completion. PEMDAS stands for:

Parentheses, Exponents, Multiplication and Division, Addition and Subtraction.

For this problem, we do the parentheses first. Inside the parentheses solve the exponent before doing addition and subtraction. Once the parentheses are solved complete the division before addition to get a final answer of 5:

\(\displaystyle 4+6\div (3^{2}+4-7)\)

\(\displaystyle 4+6\div (9+4-7)\)

\(\displaystyle 4+6\div (13-7)\)

\(\displaystyle 4+6\div6\)

\(\displaystyle 4+1=5\)