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Pre-Calculus › Pre-Calculus
Is the following function symmetrical about the y axis (is it an even function)?
Yes
No
Insufficient Information
Not a function
Explanation
For a function to be even, it must satisfy the equality
Likewise if a function is even, it is symmetrical about the y-axis
Therefore, the function is not even, and so the answer is No
Find the component form of the vector with
initial point
and
terminal point .
Explanation
To find the vector in component form given the initial and terminal points, simply subtract the initial point from the terminal point.
Find the first derivative of
in relation to .
Explanation
To find the derviative of this equation recall the power rule that states: Multiply the exponent in front of the constant and then subtract one from the exponent.
We can work individually with each term:
Derivative of
is,
For the next term:
Derivative of :
So answer is:
Anything to a power of 0 is 1.
For the next term:
Derivative of :
Any derivative of a constant is .
So the first derivative of
is
Which of the following is and accurate graph of ?





Explanation
Remember , for
.
Step 1, realize where starts: A) observe
never occurs, B) zero-out the radical component of
;
C) The resulting point is .
Step 2, find simple points for after
:
, so use
;
The next resulting point; .
, so use
;
The next resulting point; .
Step 3, draw a curve through the considered points.
Solve the following polynomial for by factoring:
Explanation
The polynomial in the problem is given as follows:
Factoring this polynomial, we would get an expression of the form:
So we need to determine what a and b are. We know we need two factors that when multiplied equal -12, and when added equal -1. If we consider 2 and 6, we could get -12 but could not arrange them in any way that would make their sum equal to -1. We then look at 3 and 4, whose product can be -12 is one of them is negative, and whose sum can be -1 if -4 is added to 3. This tells us that the 4 must be the negative factor and the 3 must be the positive factor, so we get the following:
Write an equation in slope-intercept form of the line with the given parametric equations:
Explanation
Start by solving each parametric equation for t:
Next, write an equation involving the expressions for t; since both are equal to t, we can set them equal to one another:
Multiply both sides by the LCD, 6:
Get y by itself to represent this as an equation in slope-intercept (y = mx + b) form:
Find the component form of the vector with
initial point
and
terminal point .
Explanation
To find the vector in component form given the initial and terminal points, simply subtract the initial point from the terminal point.
Write the parametric equation for the line y = 5x - 3.
x = 5t - 3
y = t
x = t
y = 5t - 3
x = 5t - 3
y = 5t - 3
x = t
y = t
Explanation
In the equation y = 5x - 3, x is the independent variable and y is the dependent variable. In a parametric equation, t is the independent variable, and x and y are both dependent variables.
Start by setting the independent variables x and t equal to one another, and then you can write two parametric equations in terms of t:
x = t
y = 5t - 3
Determine the values for the points of inflection of the following function:
Explanation
To solve, you must set the second derivative equal to 0 and solve for x. To differentiate twice, use the power rule as outlined below:
Power Rule:
Therefore:
Remember, the derivative a constant is 0.
Now, set it equal to 0. Thus,
Solve this equation and check your answer:
No solution
Explanation
To solve this, first, find the common denominator. It is (n+1)(n-2). Multiply the entire equation by this:
Simplify to get:
Expand to get:
Move all terms to one side and combine to get:
Use the quadratic formula to get: