We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

PSAT Math : How to find the probability of an outcome

Study concepts, example questions & explanations for PSAT Math

Create An Account

All PSAT Math Resources

10 Diagnostic Tests 421 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #152 : Statistics

A bag contains the following numbers of apples: 12 red delicious, 10 granny smith, and 7 fuji apples. If an apple is selected at random, what is the probability it is either a granny smith or a fuji apple?

Possible Answers:

$\small \frac{3}{29}$

$\small \frac{17}{29}$

$\small \frac{19}{29}$

$\small \frac{7}{29}$

$\small \frac{12}{29}$

Correct answer:

$\small \frac{17}{29}$

Explanation:

Probability = desired outcomes divided by total possible outcomes. Desired outcome can be either fuji or granny smith.

Desired outcomes =7+10=17

Total outcomes =12+10+7=29

$\small \frac{17}{29}$

Report an Error

Example Question #54 : Probability

From a class consisting of 15 girls and 12 boys, two students are chosen at random to be class representatives. What is the probability that neither of the two students chosen is a boy?

Possible Answers:

$\small \frac{44}{234}$

$\small \frac{16}{81}$

$\small \frac{35}{117}$

$\small \frac{25}{81}$

$\small \frac{44}{117}$

Correct answer:

$\small \frac{35}{117}$

Explanation:

To satisfy the question, BOTH students chosen must be girls.

First selection: 15 girls of 27 total students:

$\small \small \frac{15}{27}=\frac{5}{9}$

Second selection: 14 girls out of 26 total students:

$\small \frac{14}{26}=\frac{7}{13}$

$\small \frac{5}{9}\times\frac{7}{13}=\frac{35}{117}$

Report an Error

Example Question #61 : How To Find The Probability Of An Outcome

If 2 six-sided dice, each with sides numbered 1-6, are rolled, what is the probability that the sum of the numbers on the face-up sides is equal to 7?

Possible Answers:

$\small \frac{1}{4}$

$\small \frac{1}{12}$

$\small \frac{1}{6}$

$\small \frac{1}{3}$

$\small \frac{5}{36}$

Correct answer:

$\small \frac{1}{6}$

Explanation:

Probability = desired outcomes divided by total possible outcomes.

Desired outcomes = 6 (1,6; 2,5; 3,4; 4,3; 5,2; 6;1)

Total outcomes - 36 $\left ( 6\times 6 \right )$

$\small \frac{6}{36}\:=\:\frac{1}{6}$

Report an Error

Example Question #61 : How To Find The Probability Of An Outcome

If an 8-sided die is rolled 3 times, what is the probability that the same number will be rolled each time?

Possible Answers:

$\small \frac{1}{16}$

$\small \frac{1}{24}$

$\small \frac{1}{64}$

$\small \frac{1}{512}$

$\small \frac{1}{256}$

Correct answer:

$\small \frac{1}{64}$

Explanation:

$\small \textup{The first roll can be any number, so we only need be concerned with the}$

$\small \textup{2nd and 3rd rolls, each of which have a}\,\frac{1}{8}\,\textup{chance of being the same as the first}$

$\small \frac{1}{8}\times\frac{1}{8}=\frac{1}{64}$

Another way to look a it is there are 512 total possible outcomes $\left ( 8\times 8\times 8 \right )$ and 8 desired outcomes.

$\small \frac{8}{512}=\frac{1}{64}$

Report an Error

Example Question #61 : How To Find The Probability Of An Outcome

If a two-sided coin is flipped four times, what is the probability of never getting a head?

Possible Answers:

$\frac{1}{2}$

$\frac{3}{8}$

$\frac{5}{16}$

$\frac{7}{16}$

$\frac{1}{16}$

Correct answer:

$\frac{1}{16}$

Explanation:

The probability of never getting a head is the same as always getting tails. This is $\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=\frac{1}{16}$ .

Report an Error

Example Question #62 : How To Find The Probability Of An Outcome

If a six-sided die is thrown four times, what is the probability of getting a four everytime?

Possible Answers:

$\frac{1}{7776}$

$\frac{1}{50}$

$\frac{1}{1296}$

$\frac{1}{216}$

$\frac{1}{2}$

Correct answer:

$\frac{1}{1296}$

Explanation:

The probability is $\frac{1}{6}\times \frac{1}{6}\times \frac{1}{6}\times \frac{1}{6}=\frac{1}{1296}$ .

Report an Error

Example Question #161 : Statistics

If there are 9 marbles in a bag, three white, three blue, and three red, what is the probability of selecting three red marbles at random?

Possible Answers:

$\frac{1}{90}$

$\frac{1}{85}$

$\frac{1}{64}$

$\frac{1}{80}$

$\frac{1}{84}$

Correct answer:

$\frac{1}{84}$

Explanation:

The probability of selecting 3 red marbles is $\frac{3}{9}\times \frac{2}{8}\times \frac{1}{7}=\frac{1}{84}$ .

Report an Error

Example Question #61 : Probability

There is a box containing 2 red marbles, 7 blue marbles, and an unknown number of green marbles. If the probably of drawing a red marble is 10%, what is the probably that one draws a green marble?

Possible Answers:

$50\%$

$55\%$

$20\%$

$70\%$

$60\%$

Correct answer:

$55\%$

Explanation:

Let $x$ be the total number of marbles in the box. Since there's a 10% chance of drawing a red marble, then $0.1x=2$ implies there are 20 marbles total in the box. Thus, there are only 11 green marbles, resulting in the probability of drawing a green marble being $\frac{11}{20}=55\%$

Report an Error

Example Question #62 : Probability

A person rolls a fair 6-sided die twice. What is the probability that the sum of the two rolls is 3?

Possible Answers:

$\frac{1}{3}$

$\frac{1}{36}$

$\frac{1}{9}$

$\frac{1}{18}$

$\frac{2}{9}$

Correct answer:

$\frac{1}{18}$

Explanation:

In order for the sum to be 3, the two rolls must be 1 and 2. However, it doesn't matter which one comes first. Therefore, there are 2 ways we can acquire the sum being 3. The total number of combination of two die is $6\cdot 6=36$ .

Thus, the probability of rolling a sum of 3 is $\frac{2}{36}=\frac{1}{18}$ .

Report an Error

Example Question #63 : How To Find The Probability Of An Outcome

A card is drawn randomly from a stardard 52-card deck. What is the probability of drawing a four of hearts?

Possible Answers:

$\frac{1}{4}$

$\frac{2}{13}$

$\frac{1}{13}$

$\frac{1}{52}$

$\frac{3}{52}$

Correct answer:

$\frac{1}{52}$

Explanation:

The question is asking for the probability of drawing a 4 AND a Heart.

Prob(draw a 4) $=\frac{4}{52}=\frac{1}{13}$ .

Prob(draw a Heart) $=\frac{13}{52}=\frac{1}{4}$ .

Then the Prob(4 AND Heart) = Prob(4) * Prob(Heart) $=\frac{1}{13}\cdot \frac{1}{4}=\frac{1}{52}$

You can also solve this question using logic instead of the rules of probability. We know there is only one four of hearts in a deck of cards, so the probability of drawing one must be $\frac{1}{52}$ .

Report an Error

View PSAT Mathematics Tutors

Michael
Certified Tutor

St. Francis College, Bachelor of Science, Mathematics. St John's University-New York, Master of Science, Education.

View PSAT Mathematics Tutors

Nicholas
Certified Tutor

University of California-San Diego, Bachelor of Science, Applied Mathematics.

View PSAT Mathematics Tutors

Ann
Certified Tutor

Wright State University-Main Campus, Bachelor of Science, Mathematics and Computer Science. Western Governors University, Mas...

All PSAT Math Resources

10 Diagnostic Tests 421 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

ISEE Tutors in Boston, Spanish Tutors in San Diego, Algebra Tutors in San Diego, SAT Tutors in Chicago, Calculus Tutors in Philadelphia, English Tutors in Miami, GRE Tutors in Phoenix, Math Tutors in Seattle, French Tutors in Washington DC, Calculus Tutors in Dallas Fort Worth

Popular Courses & Classes

GMAT Courses & Classes in Denver, ACT Courses & Classes in Seattle, ACT Courses & Classes in Dallas Fort Worth, LSAT Courses & Classes in Atlanta, Spanish Courses & Classes in Houston, MCAT Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Dallas Fort Worth, SAT Courses & Classes in Boston, GRE Courses & Classes in New York City, LSAT Courses & Classes in Dallas Fort Worth

Popular Test Prep

ACT Test Prep in Dallas Fort Worth, LSAT Test Prep in Atlanta, GMAT Test Prep in Boston, GRE Test Prep in Chicago, ACT Test Prep in Seattle, ACT Test Prep in New York City, MCAT Test Prep in Philadelphia, LSAT Test Prep in Phoenix, LSAT Test Prep in Dallas Fort Worth, ISEE Test Prep in Philadelphia

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

PSAT Math : How to find the probability of an outcome

Study concepts, example questions & explanations for PSAT Math

All PSAT Math Resources

Example Questions

Example Question #152 : Statistics

Example Question #54 : Probability

Example Question #61 : How To Find The Probability Of An Outcome

Example Question #61 : How To Find The Probability Of An Outcome

Example Question #61 : How To Find The Probability Of An Outcome

Example Question #62 : How To Find The Probability Of An Outcome

Example Question #161 : Statistics

Example Question #61 : Probability

Example Question #62 : Probability

Example Question #63 : How To Find The Probability Of An Outcome

All PSAT Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: