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SAT Math : Basic Squaring / Square Roots

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Example Questions

Example Question #71 : Basic Squaring / Square Roots

Simplify: $\frac{\sqrt{120}}{6}$

Possible Answers:

$\frac{\sqrt{30}}{6}$

$\frac{\sqrt{30}}{3}$

$\frac{\sqrt{30}}{4}$

$\frac{\sqrt{6}}{4}$

$\frac{\sqrt{6}}{2}$

Correct answer:

$\frac{\sqrt{30}}{3}$

Explanation:

To simplify a square root, we need to find perfect squares. In this case, it is .

$\frac{\sqrt{120}}{6}=\frac{\sqrt{4}*\sqrt{30}}{6}=\frac{2\sqrt{30}}{6}=\frac{\sqrt{30}}{3}$

Remember you can reduce the fraction even further.

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Example Question #71 : Basic Squaring / Square Roots

Simplify: $\sqrt{128}$

Possible Answers:

$8\sqrt{8}$

$4\sqrt{8}$

$16\sqrt{2}$

$8\sqrt{2}$

$4\sqrt{2}$

Correct answer:

$8\sqrt{2}$

Explanation:

To simplify radicals, we need to factor out perfect squares. In this case, it's .

$\sqrt{128}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$

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Example Question #72 : Basic Squaring / Square Roots

Simplify: $\sqrt{448}$

Possible Answers:

$8\sqrt{7}$

$16\sqrt{7}$

$64\sqrt{7}$

$7\sqrt{8}$

$12\sqrt{7}$

Correct answer:

$8\sqrt{7}$

Explanation:

To simplify square roots, we need to factor out perfect squares. In this case, it's .

$\sqrt{448}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$

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Example Question #73 : Basic Squaring / Square Roots

Simplify: $\sqrt{x^5}$

Possible Answers:

$x^3\sqrt{x^2}$

$x^2\sqrt{x}$

$x\sqrt{x}$

$x^2\sqrt{x^3}$

$x^4\sqrt{x}$

Correct answer:

$x^2\sqrt{x}$

Explanation:

To simplify the radical, we should factor out perfect squares.

$\sqrt{x^5}=\sqrt{x^2}*\sqrt{x^2}*\sqrt{x}=x*x\sqrt{x}=x^2\sqrt{x}$

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Example Question #74 : Basic Squaring / Square Roots

Simplify: $\sqrt{x^7y^3}$

Possible Answers:

$x^2y\sqrt{x^3y}$

$x^3\sqrt{xy^3}$

$x^6y^2\sqrt{xy}$

$xy\sqrt{x^3y^2}$

$x^3y\sqrt{xy}$

Correct answer:

$x^3y\sqrt{xy}$

Explanation:

To simplify the square roots, we need to factor out the perfect squares.

$\sqrt{x^7y^3}=\sqrt{x^2}*\sqrt{x^2}*\sqrt{x^2}*\sqrt{y^2}*\sqrt{xy}=x^3y\sqrt{xy}$

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Example Question #44 : Simplifying Square Roots

Simplify: $\sqrt{4^5*5^4}$

Possible Answers:

$2^4*5^4\sqrt{2}$

$2^3*5^2\sqrt{32}$

$2^5*5^2\sqrt{5}$

2^5*5^2

$2^4*5^2\sqrt{10}$

Correct answer:

2^5*5^2

Explanation:

To simplify the square roots, we need to factor out perfect squares.

$\sqrt{4^5*5^4}=\sqrt{4^2}*\sqrt{4^2}*\sqrt{4}*\sqrt{5^2}*\sqrt{5^2}=4*4*2*5*5$

We can combine to have two different bases. Remember 4=2^2 .

4*4*2*5*5=2^2*2^2*2*5^2=2^5*5^2

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Example Question #75 : Basic Squaring / Square Roots

Simplify: $\sqrt{(-8)^8}$

Possible Answers:

$8^{16}$

-8^6

8^8

-8^4

8^4

Correct answer:

8^4

Explanation:

To simplify the square root, we need to determine the value of the exponent and then simplify the radical.

$\sqrt{(-8)^8}=\sqrt{8^8}$ Now let's find perfect squares.

$\sqrt{8^8}=\sqrt{8^4}*\sqrt{8^4}=8^2*8^2=8^4$

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Example Question #76 : Basic Squaring / Square Roots

Simplify: $\sqrt{(-9)^{10}}$

Possible Answers:

-9^5

$9^{-5}$

$9^{10}$

$-9^{-5}$

9^5

Correct answer:

9^5

Explanation:

To simplify the square root, we need to determine the value of the exponent and then simplify the radical.

$\sqrt{(-9)^{10}}=\sqrt{9^{10}}$ Now let's find perfect squares.

$\sqrt{9^{10}}=\sqrt{9^5}*\sqrt{9^5}=9^{2}*9^2*\sqrt{9}*\sqrt{9}=9^4*9=9^5$

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Example Question #77 : Basic Squaring / Square Roots

Simplify: $\frac{\sqrt{48}}{2}$

Possible Answers:

$4\sqrt{3}$

$\sqrt{24}$

$2\sqrt{3}$

$\frac{4\sqrt{3}}{3}$

$\frac{\sqrt{3}}{2}$

Correct answer:

$2\sqrt{3}$

Explanation:

To simplify the radical, we need to find perfect squares. Then if possible, we can reduc the fraction.

$\sqrt{48}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$

$\frac{4\sqrt{3}}{2}=2\sqrt{3}$

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Example Question #78 : Basic Squaring / Square Roots

Simplify: $\frac{\sqrt{(-8)^4}}{12}$

Possible Answers:

$\frac{16}{3}$

$\frac{8}{3}$

$\frac{64}{3}$

$-\frac{16}{3}$

$-\frac{64}{3}$

Correct answer:

$\frac{16}{3}$

Explanation:

To simplify the radical, let's deal with the parentheses first and apply the exponents. Reduce if necessary.

$\sqrt{(-8)^4}=\sqrt{8^4}=8^2=64$

$\frac{64}{12}=\frac{64\div4}{12\div4}=\frac{16}{3}$

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SAT Math : Basic Squaring / Square Roots

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #71 : Basic Squaring / Square Roots

Example Question #71 : Basic Squaring / Square Roots

Example Question #72 : Basic Squaring / Square Roots

Example Question #73 : Basic Squaring / Square Roots

Example Question #74 : Basic Squaring / Square Roots

Example Question #44 : Simplifying Square Roots

Example Question #75 : Basic Squaring / Square Roots

Example Question #76 : Basic Squaring / Square Roots

Example Question #77 : Basic Squaring / Square Roots

Example Question #78 : Basic Squaring / Square Roots

All SAT Math Resources

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