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SAT Math : How to simplify an expression

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Example Questions

Example Question #141 : Expressions

$\frac{1}{u+1} = t$ . $u \ne -1, u \ne 4$ .

Which of the following is equal to $\frac{1}{u-4}$ ?

Possible Answers:

$\frac{5t}{1-t}$

t+5

$\frac{1-5t}{t}$

$\frac{t}{1-5t}$

$\frac{t}{t-5}$

Correct answer:

$\frac{t}{1-5t}$

Explanation:

Take the reciprocal of both expressions:

$\frac{1}{u+1} = t$

$u+1 = \frac{1}{t}$

Subtract 5 from both sides:

$u+1-5 = \frac{1}{t}-5$

$u-4 = \frac{1}{t}-5$

Rewrite the expression at left and simplify it:

$u-4 = \frac{1}{t}-\frac{5t}{t}$

$u-4 = \frac{1-5t}{t}$

Take the reciprocal of both expressions:

$\frac{1}{u-4} = \frac{t}{1-5t}$

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Example Question #141 : Expressions

$\sqrt{x+ 1} = t$ ; $x \ge 7$

Which of the following is equal to $\sqrt{x- 7}$ ?

Possible Answers:

$\sqrt{t^{2} -64 }$

$\sqrt{t^{2} -8}$

$t - 2 \sqrt{2}$

t -8

$t -1 - \sqrt{7}$

Correct answer:

$\sqrt{t^{2} -8}$

Explanation:

Square both expressions

$(\sqrt{x+ 1} )^{2}= t^{2}$

$x+1 = t^{2}$

Subtract 8 from both sides:

$x+1-8 = t^{2} -8$

$x-7= t^{2} - 8$

Take the positive square root of both sides:

$\sqrt{x-7}= \sqrt{t^{2} -8}$

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Example Question #143 : Expressions

$\sqrt{x+ 1} = t$ for $x \ge -1$ .

Which of the following is equal to $\sqrt{x+ 7}$ ?

Possible Answers:

$t-1+ \sqrt{7}$

t+ 6

$t+ \sqrt{6}$

$\sqrt{t^{2} + 3 6}$

$\sqrt{t^{2} + 6}$

Correct answer:

$\sqrt{t^{2} + 6}$

Explanation:

Square both expressions

$(\sqrt{x+ 1} )^{2}= t^{2}$

$x+1 = t^{2}$

Add 6 to both sides:

$x+1+ 6 = t^{2} + 6$

$x+7= t^{2} + 6$

Take the square root of both sides:

$\sqrt{x+7}= \sqrt{t^{2} + 6}$

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Example Question #144 : Expressions

$(x+1) ^{2} = t$ . is a positive number.

Which of the following is equal to $(x+ 5)^{2}$ ?

Possible Answers:

$t +12\sqrt{ t} +36$

$t -12\sqrt{ t} +36$

$t + 8\sqrt{ t} +16$

None of the other choices gives the correct response.

$t -8\sqrt{ t} +16$

Correct answer:

$t + 8\sqrt{ t} +16$

Explanation:

$(x+1) ^{2} = t$ , so, taking the square root of both sides:

$x+1 = \pm\sqrt{ t}$

is positive, so x+1 is as well; therefore,

$x+1 = \sqrt{ t}$

Add 4 to both sides:

$x+1 + 4 = \sqrt{ t} + 4$

$x+5 =\sqrt{ t} + 4$

Square both sides, and apply the binomial square pattern to the right expression:

$(x+5 )^{2}= (\sqrt{ t} + 4)^{2}$

$= (\sqrt{ t})^{2}+ 2\cdot4 \cdot (\sqrt{ t}) +4 ^{2}$

$=t + 8\sqrt{ t} +16$

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Example Question #145 : Expressions

$\frac{1}{u+1} = t$ . $u \ne -1, u \ne -5$ .

Which of the following is equal to $\frac{1}{u+5}$ ?

Possible Answers:

$\frac{4}{1+4t}$

$\frac{t}{1+4t}$

$\frac{t+4}{4}$

$\frac{t}{t+4 }$

$\frac{4}{t+4 }$

Correct answer:

$\frac{t}{1+4t}$

Explanation:

Take the reciprocal of both expressions:

$\frac{1}{u+1} = t$

$u+1 = \frac{1}{t}$

Add 4 to both sides:

$u+1+ 4 = \frac{1}{t}+ 4$

$u+5 = \frac{1}{t}+ 4$

Rewrite the expression at left and simplify it:

$u+5 = \frac{1}{t}+ \frac{4t}{t}$

$u+5 = \frac{1+4t}{t}$

Take the reciprocal of both expressions:

$\frac{1}{u+5} = \frac{t}{1+4t}$

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Example Question #22 : Simplifying Expressions

Simplify the following expression: x³ - 4(x² + 3) + 15

Possible Answers:

x^3-4x^2+3

x^3-3x^2+15

x^5+3

x^3-4x^2+3

x^3-12x^2+15

x^5+3

Correct answer:

x^3-4x^2+3

Explanation:

To simplify this expression, you must combine like terms. You should first use the distributive property and multiply -4 by x²and -4 by 3.

x³ - 4x² -12 + 15

You can then add -12 and 15, which equals 3.

You now have x³ - 4x² + 3 and are finished. Just a reminder that x³ and 4x²are not like terms as the x’s have different exponents.

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SAT Math : How to simplify an expression

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #141 : Expressions

Example Question #141 : Expressions

Example Question #143 : Expressions

Example Question #144 : Expressions

Example Question #145 : Expressions

Example Question #22 : Simplifying Expressions

All SAT Math Resources

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