In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this:

In order to find the percentage equivalent of a decimal, the decimal has to be multiplied by 100. However, since it is multiplication by a power of 10, we can accomplish the same thing, by moving the decimal point 2 places to the right, thus making the number larger. For this problem, that looks like this: