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SAT Math : SAT Mathematics

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Example Questions

Example Question #12 : Arithmetic

what is

√0.0000490

Possible Answers:

0.07

0.00007

0.007

Correct answer:

0.007

Explanation:

easiest way to simplify: turn into scientific notation

√0.0000490= √4.9 X 10^-5

finding the square root of an even exponent is easy, and 49 is a perfect square, so we can write out an improper scientific notation:

√4.9 X 10^-5 = √49 X 10^-6

√49 = 7; √10^-6 = 10^-3 this is equivalent to raising 10^-6 to the 1/2 power, in which case all that needs to be done is multiply the two exponents: 7 X 10^-3= 0.007

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Example Question #1 : How To Simplify Square Roots

Simplify: $\sqrt{576}$

Possible Answers:

$12\sqrt{3}$

$10\sqrt{12}$

$12\sqrt{6}$

Correct answer:

Explanation:

In order to take the square root, divide 576 by 2.

$\dpi{100} \sqrt{576}= \sqrt{2}\sqrt{288}=\sqrt{2}\sqrt{2}\sqrt{144}=\sqrt{4}\sqrt{144}=2\cdot 12=24$

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Example Question #41 : Basic Squaring / Square Roots

Simplify $(\frac{16}{81})^{1/4}$ .

Possible Answers:

$\frac{2}{3}$

$\frac{8}{81}$

$\frac{4}{81}$

$\frac{4}{9}$

$\frac{2}{81}$

Correct answer:

$\frac{2}{3}$

Explanation:

$(\frac{16}{81})^{1/4}$

$\frac{16^{1/4}}{81^{1/4}}$

$\frac{(2\cdot 2\cdot 2\cdot 2)^{1/4}}{(3\cdot 3\cdot 3\cdot 3)^{1/4}}$

$\frac{2}{3}$

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Example Question #42 : Basic Squaring / Square Roots

Simplfy the following radical $\sqrt{20x^{2}}$ .

Possible Answers:

$2x\sqrt{10}$

$4\sqrt{5x}$

$2\sqrt{5x^{2}}$

$2x\sqrt{5}$

Correct answer:

$2x\sqrt{5}$

Explanation:

You can rewrite the equation as $\sqrt{20x^2}=(x)\sqrt{5} \cdot \sqrt{4}$ .

This simplifies to $2x\sqrt{5}$ .

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Example Question #43 : Basic Squaring / Square Roots

Which of the following is equal to $\sqrt{75}$ ?

Possible Answers:

$3\sqrt{5}$

$5\sqrt{3}$

$7.5\sqrt{10}$

Correct answer:

$5\sqrt{3}$

Explanation:

√75 can be broken down to √25 * √3. Which simplifies to 5√3.

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Example Question #44 : Basic Squaring / Square Roots

Simplify $\sqrt{a^{3}b^{4}c^{5}}$ .

Possible Answers:

$a^{2}bc^{2}\sqrt{ac}$

$a^{2}bc\sqrt{bc}$

$a^{2}b^{2}c\sqrt{ab}$

$a^{2}b^{2}c^{2}\sqrt{bc}$

$ab^{2}c^{2}\sqrt{ac}$

Correct answer:

$ab^{2}c^{2}\sqrt{ac}$

Explanation:

Rewrite what is under the radical in terms of perfect squares:

$x^{2}=x\cdot x$

$x^{4}=x^{2}\cdot x^{2}$

$x^{6}=x^{3}\cdot x^{3}$

Therefore, $\sqrt{a^{3}b^{4}c^{5}}= \sqrt{a^{2}a^{1}b^{4}c^{4}c^{1}}=ab^{2}c^{2}\sqrt{ac}$ .

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Example Question #2 : Exponents And Roots

What is $\sqrt{50}$ ?

Possible Answers:

$5\sqrt{2}$

$2\sqrt{5}$

$10\sqrt{2}$

Correct answer:

$5\sqrt{2}$

Explanation:

We know that 25 is a factor of 50. The square root of 25 is 5. That leaves $\sqrt{2}$ which can not be simplified further.

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Example Question #45 : Basic Squaring / Square Roots

Which of the following is equivalent to $\frac{x + \sqrt{3}}{3x + \sqrt{2}}$ ?

Possible Answers:

$\frac{4x + \sqrt{5}}{3x + 2}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

$\frac{3x^{2} + 3x\sqrt{2} + x\sqrt{3} +\sqrt{6}}{9x^{2} - 2}$

$\frac{3x^{2} + \sqrt{6}}{3x - 2}$

$\frac{3x^{2} - \sqrt{6}}{9x^{2} + 2}$

Correct answer:

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

Explanation:

Multiply by the conjugate and the use the formula for the difference of two squares:

$\frac{x + \sqrt{3}}{3x + \sqrt{2}}$

$\frac{x + \sqrt{3}}{3x + \sqrt{2}}\cdot \frac{3x - \sqrt{2}}{3x - \sqrt{2}}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{(3x)^{2} - (\sqrt{2})^{2}}$

$\frac{3x^{2} -x \sqrt{2} + 3x\sqrt{3} - \sqrt{6}}{9x^{2} - 2}$

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Example Question #4 : Exponents And Roots

Which of the following is the most simplified form of:

$\sqrt{468}$

Possible Answers:

$6\sqrt{13}$

$2\sqrt{117}$

$\sqrt{468}$

$17\sqrt{2}$

$4\sqrt{29}$

Correct answer:

$6\sqrt{13}$

Explanation:

First find all of the prime factors of 468

$468=6\ast78=6\ast6\ast13=2\ast3\ast2\ast3\ast13$

So $\sqrt{468}=\sqrt{2\ast2\ast3\ast3\ast13}=2\ast3\sqrt{13}=6\sqrt{13}$

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Example Question #46 : Basic Squaring / Square Roots

What is $\sqrt{432}$ equal to?

Possible Answers:

$12\sqrt{3}$

$12\sqrt{12}$

$6\sqrt{3}$

$6\sqrt{4}$

$144\sqrt{3}$

Correct answer:

$12\sqrt{3}$

Explanation:

$\sqrt{432}$

1. We know that 432=(144)(3) , which we can separate under the square root:

$\sqrt{144\cdot 3}$

2. 144 can be taken out since it is a perfect square: $12\cdot12=144$ . This leaves us with:

$12\sqrt{3}$

This cannot be simplified any further.

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SAT Math : SAT Mathematics

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #12 : Arithmetic

Example Question #1 : How To Simplify Square Roots

Example Question #41 : Basic Squaring / Square Roots

Example Question #42 : Basic Squaring / Square Roots

Example Question #43 : Basic Squaring / Square Roots

Example Question #44 : Basic Squaring / Square Roots

Example Question #2 : Exponents And Roots

Example Question #45 : Basic Squaring / Square Roots

Example Question #4 : Exponents And Roots

Example Question #46 : Basic Squaring / Square Roots

All SAT Math Resources

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