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SSAT Elementary Level Math : How to find the perimeter of a triangle

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Example Questions

Example Question #31 : How To Find The Perimeter Of A Triangle

Find the perimeter of the triangle shown below:

Screen shot 2015 11 03 at 3.29.15 pm

Possible Answers:

$\displaystyle 78$

$\displaystyle 40$

$\displaystyle 32$

$\displaystyle 39$

$\displaystyle 26$

Correct answer:

$\displaystyle 32$

Explanation:

The perimeter is the sides added together. $\displaystyle 13+13+6=32$

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Example Question #5809 : Ssat Elementary Level Quantitative (Math)

Use the following to answer the question.

Triangle2

Find the perimeter of the triangle.

Possible Answers:

$72\text{cm}$ $\displaystyle 72\text{cm}$

$29\text{cm}$ $\displaystyle 29\text{cm}$

$72\text{cm}^2$ $\displaystyle 72\text{cm}^2$

$29\text{cm}^2$ $\displaystyle 29\text{cm}^2$

$66\text{cm}$ $\displaystyle 66\text{cm}$

Correct answer:

$29\text{cm}$ $\displaystyle 29\text{cm}$

Explanation:

To find the perimeter of a triangle, we will use the following formula:

$\text{perimeter of triangle} = a+b+c$ $\displaystyle \text{perimeter of triangle} = a+b+c$

where a, b, and c are the lengths of the sides of the triangle.

So, in the triangle

Triangle2

we can see the lengths of the sides are 11cm, 12cm, and 6cm. Knowing this, we can substitute into the formula. We get

$\text{perimeter of triangle} = 11\text{cm} + 12\text{cm} + 6\text{cm}$ $\displaystyle \text{perimeter of triangle} = 11\text{cm} + 12\text{cm} + 6\text{cm}$

$\text{perimeter of triangle} = 29\text{cm}$ $\displaystyle \text{perimeter of triangle} = 29\text{cm}$

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Example Question #5810 : Ssat Elementary Level Quantitative (Math)

Find the perimeter of an equilateral triangle with a base of 16in.

Possible Answers:

$36\text{in}$ $\displaystyle 36\text{in}$

$48\text{in}$ $\displaystyle 48\text{in}$

$32\text{in}$ $\displaystyle 32\text{in}$

$24\text{in}$ $\displaystyle 24\text{in}$

$56\text{in}$ $\displaystyle 56\text{in}$

Correct answer:

$48\text{in}$ $\displaystyle 48\text{in}$

Explanation:

To find the perimeter of a triangle, we will use the following formula:

$\text{perimeter of triangle} = a+b+c$ $\displaystyle \text{perimeter of triangle} = a+b+c$

where a, b, and c are the lengths of the sides of the triangle.

Now, we know the base of the triangle has a length of 16in. Because it is an equilateral triangle, all lengths are the same. Therefore, all lengths are 16in.

Knowing this, we can substitute into the formula. We get

$\text{perimeter of triangle} = 16\text{in} +16\text{in} +16\text{in}$ $\displaystyle \text{perimeter of triangle} = 16\text{in} +16\text{in} +16\text{in}$

$\text{perimeter of triangle} = 48\text{in}$ $\displaystyle \text{perimeter of triangle} = 48\text{in}$

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Example Question #5811 : Ssat Elementary Level Quantitative (Math)

The perimeter of an equilateral triangle is 27in. Find the length of one side of the triangle.

Possible Answers:

$8\text{in}$ $\displaystyle 8\text{in}$

$7\text{in}$ $\displaystyle 7\text{in}$

$9\text{in}$ $\displaystyle 9\text{in}$

$12\text{in}$ $\displaystyle 12\text{in}$

$11\text{in}$ $\displaystyle 11\text{in}$

Correct answer:

$9\text{in}$ $\displaystyle 9\text{in}$

Explanation:

To find the perimeter of an equilateral triangle, we will use this formula:

P = 3a $\displaystyle P = 3a$

where a is the length of one side. Now, to find the length of one side, we will solve for a.

We know the perimeter of the triangle is 27in. So, we will substitute. We get

$27\text{in} = 3a$ $\displaystyle 27\text{in} = 3a$

$\frac{27\text{in}}{3} = \frac{3a}{3}$ $\displaystyle \frac{27\text{in}}{3} = \frac{3a}{3}$

$9\text{in} = a$ $\displaystyle 9\text{in} = a$

$a = 9\text{in}$ $\displaystyle a = 9\text{in}$

Therefore, the length of one side of the triangle is 9in.

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Example Question #5812 : Ssat Elementary Level Quantitative (Math)

Use the following triangle to solve the problem:

Triangle2

Find the perimeter.

Possible Answers:

$23\text{cm}$ $\displaystyle 23\text{cm}$

$18\text{cm}$ $\displaystyle 18\text{cm}$

$29\text{cm}$ $\displaystyle 29\text{cm}$

$12\text{cm}$ $\displaystyle 12\text{cm}$

$9\text{cm}$ $\displaystyle 9\text{cm}$

Correct answer:

$29\text{cm}$ $\displaystyle 29\text{cm}$

Explanation:

To find the perimeter of a triangle, we will use the following formula:

$\displaystyle P = a+b+c$

where a, b, and c are the lengths of the sides of the triangle.

Now, given the triangle

Triangle2

we can see it has sides of length 11cm, 6cm, and 12cm. So, we can substitute. We get

$P = 11\text{cm} + 6\text{cm} + 12\text{cm}$ $\displaystyle P = 11\text{cm} + 6\text{cm} + 12\text{cm}$

$P = 29\text{cm}$ $\displaystyle P = 29\text{cm}$

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SSAT Elementary Level Math : How to find the perimeter of a triangle

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #31 : How To Find The Perimeter Of A Triangle

Example Question #5809 : Ssat Elementary Level Quantitative (Math)

Example Question #5810 : Ssat Elementary Level Quantitative (Math)

Example Question #5811 : Ssat Elementary Level Quantitative (Math)

Example Question #5812 : Ssat Elementary Level Quantitative (Math)

All SSAT Elementary Level Math Resources

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