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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #972 : Common Core Math: Grade 3

$\frac{\begin{array}[b]{r}60\\ \times\ 7\end{array}}{ \ \ \ \space}$

Possible Answers:

450

420

430

410

440

Correct answer:

420

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$7\times0=0$

$7\times6=42$

$\frac{\begin{array}[b]{r}60\\ \times\ 7\end{array}}{ \ \space420}$

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Example Question #173 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

$\frac{\begin{array}[b]{r}70\\ \times\ 8\end{array}}{ \ \ \ \space}$

Possible Answers:

570

530

540

560

550

Correct answer:

560

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$8\times0=0$

$8\times7=56$

$\frac{\begin{array}[b]{r}70\\ \times\ 8\end{array}}{ \ \space560}$

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Example Question #3161 : Ssat Elementary Level Quantitative (Math)

$\frac{\begin{array}[b]{r}70\\ \times\ 9\end{array}}{ \ \ \ \space}$

Possible Answers:

670

660

640

650

630

Correct answer:

630

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$9\times0=0$

$9\times7=63$

$\frac{\begin{array}[b]{r}70\\ \times\ 9\end{array}}{ \ \space630}$

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Example Question #172 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

$\frac{\begin{array}[b]{r}80\\ \times\ 9\end{array}}{ \ \ \ \space}$

Possible Answers:

740

710

730

700

720

Correct answer:

720

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$9\times0=0$

$9\times8=72$

$\frac{\begin{array}[b]{r}80\\ \times\ 9\end{array}}{ \ \space720}$

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Example Question #91 : How To Multiply Variables

$\frac{\begin{array}[b]{r}10\\ \times\ 1\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$1\times0=0$

$1\times1=1$

$\frac{\begin{array}[b]{r}10\\ \times\ 1\end{array}}{ \ \ \space10}$

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Example Question #171 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

$\frac{\begin{array}[b]{r}40\\ \times\ 2\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$2\times0=0$

$2\times4=8$

$\frac{\begin{array}[b]{r}40\\ \times\ 2\end{array}}{ \ \ \space80}$

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Example Question #3161 : Numbers And Operations

Megan is working on a science experiment. She needs times the amount of water that she has shown on the scale below. How much water does she need?

15 g

Possible Answers:

40g

50g

60g

55g

45g

Correct answer:

60g

Explanation:

Megan has 15g . If she needs times that amount, we can multiply to find our answer.

$\frac{\begin{array}[b]{r}15\\ \times\ 4\end{array}}{ \ \ \ \ \space 60g}$

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Example Question #3162 : Numbers And Operations

Megan is working on a science experiment. She needs times the amount of water that she has shown on the scale below. How much water does she need?

19 g

Possible Answers:

82g

84g

72g

70g

76g

Correct answer:

76g

Explanation:

Megan has 19g . If she needs times that amount, we can multiply to find our answer.

$\frac{\begin{array}[b]{r}19\\ \times\ 4\end{array}}{ \ \ \ \space 76g}$

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Example Question #3163 : Numbers And Operations

Megan is working on a science experiment. She needs times the amount of water that she has shown on the scale below. How much water does she need?

11 g

Possible Answers:

56g

40g

48g

52g

44g

Correct answer:

44g

Explanation:

Megan has 11g of water. If she needs times that amount, we can multiply to find our answer.

$\frac{\begin{array}[b]{r}11\\ \times\ 4\end{array}}{ \ \ \ \ \ \space 44g}$

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Example Question #13 : Common Core Math: Grade 4

What equation is described below?

is times as many as

Possible Answers:

50-1=49

49+1=49

$49\times1=49$

48+1=49

$49\div1=49$

Correct answer:

$49\times1=49$

Explanation:

is times the amount of

In this phrase, "is" represents equal and "times" means multiplication.

So we have $49\times1=49$

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #972 : Common Core Math: Grade 3

Example Question #173 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

Example Question #3161 : Ssat Elementary Level Quantitative (Math)

Example Question #172 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

Example Question #91 : How To Multiply Variables

Example Question #171 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

Example Question #3161 : Numbers And Operations

Example Question #3162 : Numbers And Operations

Example Question #3163 : Numbers And Operations

Example Question #13 : Common Core Math: Grade 4

All SSAT Elementary Level Math Resources

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