To find the resultant we must sum the two vectors:

Now we must graph the resultant

First, we must understand what we are solving for.  We are solving for the angle that is formed by  and the x-axis.  To do this, we can extend a vector from the origin which stops directly under the end of .  We will call this new vector  and it will be 7 units long.  We will also extend a vector upwards that is perpendicular to the x-axis.  We will call this  and it will be 3 units long.

Now we can use the relationship that  where  is the adjacent side and  is the opposite side.

And so  is 23.2 degrees above the x-axis.

When finding the difference of two vectors, you must subtract the x and y components separately.

To find the difference of two vectors we must consider the x and y components separately.

And then we must correctly graph this vector

When finding the magnitude of the vector, you use either the Pythagorean Theorem by forming a right triangle with the vector in question or you can use the distance formula.  This is much more clear considering the distance vector that the magnitude of the vector is in fact the length of the vector.

The correct image depicting an aeronautical bearing of  is 

This image begins at north, and moves  clockwise from it. 

Three of the given incorrect answers depict , , . The fourth incorrect answer does not represent a standard bearing convention as it is neither an acute angle, nor in the clockwise direction. That incorrect answer looks like:

The bearing of a point B from a point A in a horizontal plane is defined as the acute angle made by the ray drawn from A through B with the north-south line through A. The bearing is read from the north or south line toward the east or west. Bearing is typically only represented in degrees (or degrees and minutes) rather than radians. To find , start in the south direction, then move  towards the west:

The other incorrect answer choices provided depict , , and .

This question and its answer choices give you a few clues to work with. First, we need to identify the bearing angle being shown. The options in the answer choices are either , , or . Because the angle begins in the south direction and moves  towards the west, the correct bearing is . That means only two of the answer choices could be correct. We now need to understand how the  miles per hour corresponds to the problem. Notice that there is no answer choice that has the bearing of  and velocity of  miles per hour. Rather, we need to choose between  miles per hour for  hours or  miles per hour for  hours. Because  miles per hour for  hours corresponds to  (whereas the other option corresponds to only ), the correct answer is "A motorboat traveling  at  miles per hour for  hours."

First, let's set up a diagram using the given information. This looks like this:

Next, let's convert this info into a triangle so that we can use trigonometry to solve the problem. We need to calculate that the ship going  miles per hour for  hours will have traveled  miles. 

Now we can use trigonometry to determine the missing sides, s and e.

Therefore the ship has travelled 181.87 miles south and 105 miles east. 

First, let's incorporate the given information into a diagram. Start by labelling the plane's bearing of  along with its velocity 330km. Next, draw a line segment to complete the triangle and determine the measures of the angles of the triangle. We can determine the angle , we constructed the diagram such that there is a right angle, and finally we can find the third angle by taking . 

The question is asking us how far south and how far east the plane is from its starting point, so we need to now use trigonometry to determine the lengths of the missing sides of the triangle. We will call these sides s for the southward distance and e for the eastward distance.

 km

 km

Therefore the airplane is 139.46 km south of its starting point and 299.08 km east of its starting point.