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Example Questions
Example Question #61 : Trigonometric Equations
Find the roots of the equation
Factor the equation:
The roots occur when each factor equals 0:
Example Question #62 : Trigonometric Equations
Find all roots of this equation, in radians.
Take the square root of both sides:
This gives us two roots,
and
Solving for x:
or
,
which evaluate to and
Now we check to make sure both answers work. Make sure your calculator is in radians mode!
Our answers are
Example Question #63 : Trigonometric Equations
If What is
in degrees?
if is
Example Question #61 : Trigonometric Equations
Solve the following equation for .
No solution exists
; Use the double angle identity for cosine.
; Move everything to the left side of the equation.
; This is a quadratic-like expression that cannot be factored. We must use the quadratic formula. It may be helpful to see this if you replace
with
, so it becomes:
Recall the quadratic formula
plug in .
We now have
; Separate this into two equations and take the inverse sine.
or
The first equation gives us . Using the unit circle as we did in previous problems, we can find a second answer from this which is
. The second equation will not give us a solution.
Example Question #31 : Solving Trigonometric Equations
What are the zeros of the function listed above for the interval .
When the quadratic formula is applied to the function, it yields
So those are the zeros for sine, but sine has a minimum of -1, so -2 is out. For -1/2, sine achieves that twice in a cycle, at π+π/6 and 2π-π/6. So while -π/6 is true, it is not correct since it is not in the given interval.
Therefore on the given interval the zeros are:
Example Question #3 : Quadratic Formula With Trigonometry
Solve the following trigonometric equation:
for
The equation does not have a solution.
Since can be written as:
. We can't have
.
Therefore . This means that
where k is an integer.
since . We have x=0 is the only number that satisfies this property.
Example Question #62 : Trigonometric Equations
Solve each equation over the domain (answer in degrees).
Rearrange the problem,
Over the interval 0 to 360 degrees, cosx = 1/2 at 60 degrees and 300 degrees.
Example Question #62 : Trigonometric Equations
Solve the equation over the interval
First, get the equation in terms of one trig function. We can do this by substituting in using the Pythagorean Identity for .
Then we have .
Bring all the terms to one side to find that .
We can factor this quadratic to .
This means that .
The only angle value for which this is true is .
Example Question #63 : Trigonometric Equations
Solve for , giving your answer as a positive angle measure:
No solution
First, re-write the equation so that it is equal to zero:
Now we can use the quadratic formula to solve for x. In this case, the coefficients a, b, and c are a=1, b=2, and c=-3:
simplify
This gives two potential answers:
and
Sine must be between -1 and 1, so there are no values of x that would give a sine of -3. The only solution that works is . The only angle measure that has a sine of 1 is
.
Example Question #1 : Quadratic Formula With Trigonometry
Solve for :
.
Give your answer as a positive angle measure.
Use the quadratic formula to solve for x. In this case, the coefficients a, b, and c are a=4, b=1, and c=-1:
simplify
the square root of 17 is about 4.123. This gives two potential answers:
. We can solve for x by evaluating both
and
. The first gives an answer of
. Add this to 360 to get that as a positive angle measure,
. If this has a sine of -0.64, so does its reflection over the y-axis, which is
.
The second gives an answer of . If that has a sine of 0.39, then so does its reflection over the y-axis, which is
.
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