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Example Questions
Example Question #52 : Trigonometry
What is the period of the given trigonometric function:
. Leave your answer in terms of
, simplify all fractions.
To find the period of a sine, cosine, cosecant, or secant funciton use the formula:
where
comes from the general formula:
. We see that for our equation
and so the period is
when you reduce the fraction.
Example Question #1 : How To Find The Period Of The Sine
Find the period of the following formula:
To find period, simply remember the following formula:
where B is the coefficient in front of x. Thus,
Example Question #1 : How To Find The Domain Of The Sine
Find the domain of the function:
The function is related to the parent function
, which has a domain of
.
The value of theta for has no restriction and is valid for all real numbers.
The answer is .
Example Question #2971 : Act Math
What is the domain of the given trigonometric function:
For both Sine and Cosine, since there are no asymptotes like Tangent and Cotangent functions, the function can take in any value for . Thus the domain is:
Example Question #1 : How To Find The Range Of The Sine
Which of the following statements is (are) true:
I. The domain of the tangent function is all real numbers
II. The range of the sine function is all real numbers
III. The periods of the tangent, sine, and cosine functions are the same.
I and II only
I only
II and III only
II only
none of the above
II only
The domain of the tangent function does not include any values of x that are odd multiples of π/2 .
The range of the sine function is from [-1, 1].
The period of the tangent function is π, whereas the period for both sine and cosine is 2π.
Example Question #2 : How To Find The Range Of The Sine
Which of the following represents a sine wave with a range of ?
The range of a sine wave is altered by the coefficient placed in front of the base equation. So, if you have , this means that the highest point on the wave will be at
and the lowest at
. However, if you then begin to shift the equation vertically by adding values, as in,
, then you need to account for said shift. This would make the minimum value to be
and the maximum value to be
. For our question, then, it is fine to use
. The
for the function parameter only alters the period of the equation, making its waves "thinner."
Example Question #1 : How To Find The Range Of The Sine
Which of the following sine waves has a range of to
?
The range of a sine wave is altered by the coefficient placed in front of the base equation. So, if you have , this means that the highest point on the wave will be at
and the lowest at
; however, if you then begin to shift the equation vertically by adding values, as in,
, then you need to account for said shift. This would make the minimum value to be
and the maximum value to be
.
For our question, the range of values covers . This range is accomplished by having either
or
as your coefficient. (
merely flips the equation over the
-axis. The range "spread" remains the same.) We need to make the upper value to be
instead of
. To do this, you will need to add
to
. This requires an upward shift of
. An example of performing a shift like this is:
Among the possible answers, the one that works is:
The parameter does not matter, as it only alters the frequency of the function.
Example Question #1 : How To Find The Range Of The Sine
What is the range of the trigonometric function given by the equation:
The range of the sine and cosine functions are the closed interval from the negative amplitude and the positive amplitude. The amplitude is given by the coefficient, in the following general equation:
. Thus we see the range is:
Example Question #2 : How To Find The Range Of The Sine
What is the range of the following trigonometric equation:?
The range of a sine or cosine function spans from the negative amplitude to the positive amplitude. The amplitude is in the general formula:
Thus we see amplitude of our function is and so the range is:
Example Question #2 : Trigonometry
If , what is
if
is between
and
?
Recall that .
Therefore, we are looking for or
.
Now, this has a reference angle of , but it is in the third quadrant. This means that the value will be negative. The value of
is
. However, given the quadrant of our angle, it will be
.
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