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Algebra 1 : Functions and Lines

Study concepts, example questions & explanations for Algebra 1

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10 Diagnostic Tests 557 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #625 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(7, 0) \text{ and }(8,9)$ .

Possible Answers:

$\left(\frac{15}{2}, \frac{9}{2}\right)$

$\left(\frac{1}{2}, -\frac{9}{2}\right)$

$\left(\frac{7}{2}, \frac{17}{2}\right)$

(15, 9)

Correct answer:

$\left(\frac{15}{2}, \frac{9}{2}\right)$

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{7+8}{2}, \frac{0+9}{2}\right)=\left(\frac{15}{2}, \frac{9}{2}\right)$

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Example Question #626 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(100, 5)\text{ and }(2, 0)$ .

Possible Answers:

(50, 1)

$\left(51, \frac{5}{2}\right)$

$\left(50, \frac{7}{2}\right)$

(100, 0)

Correct answer:

$\left(51, \frac{5}{2}\right)$

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{100+2}{2}, \frac{5+0}{2}\right)=\left(51, \frac{5}{2}\right)$

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Example Question #627 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(-5, -2)\text{ and }(-9, -10)$ .

Possible Answers:

$\left(-\frac{15}{2}, -\frac{11}{2}\right)$

(7, 2)

(-7, -6)

(-2, -4)

Correct answer:

(-7, -6)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{-5+(-9)}{2}, \frac{-2+(-10)}{2}\right)=(-7, -6)$

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Example Question #628 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(1, -2)\text{ and }(7, -12)$ .

Possible Answers:

$\left(-\frac{13}{2}, \frac{9}{2}\right)$

(4, -7)

(-4, -7)

(3, 5)

Correct answer:

(4, -7)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{1+7}{2}, \frac{-2+(-12)}{2}\right)=(4, -7)$

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Example Question #629 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(-0.9, 1)\text{ and }(0.1, 5)$ .

Possible Answers:

(-0.5, 2)

(-0.5, -0.5)

(-0.5, 3)

(-0.4, 3)

Correct answer:

(-0.4, 3)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{-0.9+0.1}{2}, \frac{1+5}{2}\right)=(-0.4, 3)$

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Example Question #631 : Equations Of Lines

Find the midpoint of a line segment that has endpoints at $(11, -5)\text{ and }(1, -9)$ .

Possible Answers:

(6, -2)

(6, -7)

(2, 1)

(5, 4)

Correct answer:

(6, -7)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{11+1}{2}, \frac{-5+(-9)}{2}\right)=(6, -7)$

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Example Question #632 : Equations Of Lines

Find the midpoint of a line segment that has endpoints at $(-7, 12)\text{ and }(-3, -2)$ .

Possible Answers:

(-5, 5)

(-2, -2)

(-2, 6)

(5, -5)

Correct answer:

(-5, 5)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{-7+(-3)}{2}, \frac{12+(-2)}{2}\right)=(-5, 5)$

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Example Question #633 : Equations Of Lines

Find the midpoint of the line segment with the endpoints $(1, 2)\text{ and }(3, 9)$ .

Possible Answers:

$\left(2, \frac{11}{2}\right)$

$\left(-1, -\frac{7}{2}\right)$

$\left(\frac{3}{2}, 6\right)$

(4, 11)

Correct answer:

$\left(2, \frac{11}{2}\right)$

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{1+3}{2}, \frac{2+9}{2}\right)=\left(2, \frac{11}{2}\right)$

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Example Question #634 : Equations Of Lines

Find the midpoint of the line segment that has endpoints at $(8, 7)\text{ and }(2, 7)$ .

Possible Answers:

(-5, -7)

(10, 0)

(5, 7)

$\left(\frac{15}{2}, \frac{9}{2}\right)$

Correct answer:

(5, 7)

Explanation:

To find the midpoint of a line segment, take the average of the x-coordinates and the average of the y-coordinates.

$\text{Midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\frac{8+2}{2}, \frac{7+7}{2}\right)=(5, 7)$

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Example Question #635 : Equations Of Lines

Find the midpoint of the given points:

$(3,6) \,and \, (-1,2)$

Possible Answers:

(2,5)

(0,3)

(1,4)

(2,3)

(0,4)

Correct answer:

(1,4)

Explanation:

To solve for the midpoint, we want to plug in our coordinate values into the midpoint formula:

$(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

$(\frac{-1+3}{2},\frac{2+6}{2})=(\frac{2}{2},\frac{8}{2})=(1,4)$

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Algebra 1 : Functions and Lines

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #625 : Equations Of Lines

Example Question #626 : Equations Of Lines

Example Question #627 : Equations Of Lines

Example Question #628 : Equations Of Lines

Example Question #629 : Equations Of Lines

Example Question #631 : Equations Of Lines

Example Question #632 : Equations Of Lines

Example Question #633 : Equations Of Lines

Example Question #634 : Equations Of Lines

Example Question #635 : Equations Of Lines

All Algebra 1 Resources

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