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Common Core: 4th Grade Math : Solving for Length

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #5626 : Ssat Elementary Level Quantitative (Math)

What is the length of a rectangular room with a perimeter of 50ft $\displaystyle 50ft$ and a width of 7ft? $\displaystyle 7ft?$

Possible Answers:

20ft $\displaystyle 20ft$

28ft $\displaystyle 28ft$

18ft $\displaystyle 18ft$

36ft $\displaystyle 36ft$

14ft $\displaystyle 14ft$

Correct answer:

18ft $\displaystyle 18ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 50=2l+2(7)$

$\displaystyle 50=2l+14$

Subtract $\displaystyle 14$ from both sides

$\displaystyle 50-14=2l+14-14$

36=2l $\displaystyle 36=2l$

Divide $\displaystyle 2$ by both sides

$\frac{36}{2}=\frac{2l}{2}$ $\displaystyle \frac{36}{2}=\frac{2l}{2}$

18=l $\displaystyle 18=l$

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Example Question #11 : Solving For Length

What is the length of a rectangular room with an area of 56ft^2 $\displaystyle 56ft^2$ and a width of 7ft? $\displaystyle 7ft?$

Possible Answers:

5ft $\displaystyle 5ft$

8ft $\displaystyle 8ft$

6ft $\displaystyle 6ft$

7ft $\displaystyle 7ft$

9ft $\displaystyle 9ft$

Correct answer:

8ft $\displaystyle 8ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$56=l\times 7$ $\displaystyle 56=l\times 7$

$\frac{56}{7}=\frac{l\times 7}{7}$ $\displaystyle \frac{56}{7}=\frac{l\times 7}{7}$

8=l $\displaystyle 8=l$

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Example Question #61 : Parallelograms

What is the length of a rectangular room with an area of 80ft^2 $\displaystyle 80ft^2$ and a width of 8ft? $\displaystyle 8ft?$

Possible Answers:

20ft $\displaystyle 20ft$

8ft $\displaystyle 8ft$

10ft $\displaystyle 10ft$

18ft $\displaystyle 18ft$

16ft $\displaystyle 16ft$

Correct answer:

10ft $\displaystyle 10ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$80=l\times 8$ $\displaystyle 80=l\times 8$

$\frac{80}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{80}{8}=\frac{l\times 8}{8}$

10=l $\displaystyle 10=l$

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Example Question #71 : Parallelograms

What is the length of a rectangular room with an area of 100ft^2 $\displaystyle 100ft^2$ and a width of 5ft? $\displaystyle 5ft?$

Possible Answers:

20ft $\displaystyle 20ft$

10ft $\displaystyle 10ft$

25ft $\displaystyle 25ft$

30ft $\displaystyle 30ft$

15ft $\displaystyle 15ft$

Correct answer:

20ft $\displaystyle 20ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$100=l\times 5$ $\displaystyle 100=l\times 5$

$\frac{100}{5}=\frac{l\times 5}{5}$ $\displaystyle \frac{100}{5}=\frac{l\times 5}{5}$

20=l $\displaystyle 20=l$

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Example Question #72 : Parallelograms

What is the length of a rectangular room with an area of 120ft^2 $\displaystyle 120ft^2$ and a width of 10ft? $\displaystyle 10ft?$

Possible Answers:

11ft $\displaystyle 11ft$

9ft $\displaystyle 9ft$

12ft $\displaystyle 12ft$

14ft $\displaystyle 14ft$

8ft $\displaystyle 8ft$

Correct answer:

12ft $\displaystyle 12ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$120=l\times 10$ $\displaystyle 120=l\times 10$

$\frac{120}{10}=\frac{l\times 10}{10}$ $\displaystyle \frac{120}{10}=\frac{l\times 10}{10}$

12=l $\displaystyle 12=l$

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Example Question #73 : Parallelograms

What is the length of a rectangular room with an area of 48ft^2 $\displaystyle 48ft^2$ and a width of 8ft? $\displaystyle 8ft?$

Possible Answers:

9ft $\displaystyle 9ft$

7ft $\displaystyle 7ft$

8ft $\displaystyle 8ft$

5ft $\displaystyle 5ft$

6ft $\displaystyle 6ft$

Correct answer:

6ft $\displaystyle 6ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$48=l\times 8$ $\displaystyle 48=l\times 8$

$\frac{48}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{48}{8}=\frac{l\times 8}{8}$

6=l $\displaystyle 6=l$

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Example Question #101 : Plane Geometry

What is the length of a rectangular room with an area of 99ft^2 $\displaystyle 99ft^2$ and a width of 9ft? $\displaystyle 9ft?$

Possible Answers:

11ft $\displaystyle 11ft$

8ft $\displaystyle 8ft$

10ft $\displaystyle 10ft$

9ft $\displaystyle 9ft$

7ft $\displaystyle 7ft$

Correct answer:

11ft $\displaystyle 11ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$99=l\times 9$ $\displaystyle 99=l\times 9$

$\frac{99}{9}=\frac{l\times 9}{9}$ $\displaystyle \frac{99}{9}=\frac{l\times 9}{9}$

11=l $\displaystyle 11=l$

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Example Question #102 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular room with an area of 72ft^2 $\displaystyle 72ft^2$ and a width of 8ft? $\displaystyle 8ft?$

Possible Answers:

10ft $\displaystyle 10ft$

9ft $\displaystyle 9ft$

12ft $\displaystyle 12ft$

13ft $\displaystyle 13ft$

11ft $\displaystyle 11ft$

Correct answer:

9ft $\displaystyle 9ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$72=l\times 8$ $\displaystyle 72=l\times 8$

$\frac{72}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{72}{8}=\frac{l\times 8}{8}$

9=l $\displaystyle 9=l$

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Example Question #102 : Plane Geometry

What is the length of a rectangular room with an area of 80ft^2 $\displaystyle 80ft^2$ and a width of 8ft? $\displaystyle 8ft?$

Possible Answers:

10ft $\displaystyle 10ft$

8ft $\displaystyle 8ft$

7ft $\displaystyle 7ft$

6ft $\displaystyle 6ft$

9ft $\displaystyle 9ft$

Correct answer:

10ft $\displaystyle 10ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$80=l\times 8$ $\displaystyle 80=l\times 8$

$\frac{80}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{80}{8}=\frac{l\times 8}{8}$

10=l $\displaystyle 10=l$

Report an Error

Example Question #77 : Parallelograms

What is the length of a rectangular room with an area of 42ft^2 $\displaystyle 42ft^2$ and a width of 7ft? $\displaystyle 7ft?$

Possible Answers:

7ft $\displaystyle 7ft$

6ft $\displaystyle 6ft$

4ft $\displaystyle 4ft$

8ft $\displaystyle 8ft$

5ft $\displaystyle 5ft$

Correct answer:

6ft $\displaystyle 6ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$42=l\times 7$ $\displaystyle 42=l\times 7$

$\frac{42}{7}=\frac{l\times 7}{7}$ $\displaystyle \frac{42}{7}=\frac{l\times 7}{7}$

6=l $\displaystyle 6=l$

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Common Core: 4th Grade Math : Solving for Length

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #5626 : Ssat Elementary Level Quantitative (Math)

Example Question #11 : Solving For Length

Example Question #61 : Parallelograms

Example Question #71 : Parallelograms

Example Question #72 : Parallelograms

Example Question #73 : Parallelograms

Example Question #101 : Plane Geometry

Example Question #102 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #102 : Plane Geometry

Example Question #77 : Parallelograms

All Common Core: 4th Grade Math Resources

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