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Common Core: 4th Grade Math : Solving for Length

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #61 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 36m^2 and a width of 4m?

Possible Answers:

11m

12m

10m

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$36=l\times 4$

$\frac{36}{4}=\frac{l\times 4}{4}$

9=l

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Example Question #62 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 36m^2 and a width of 3m?

Possible Answers:

14m

10m

13m

11m

12m

Correct answer:

12m

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$36=l\times 3$

$\frac{36}{3}=\frac{l\times 3}{3}$

12=l

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Example Question #63 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 14m^2 and a width of 2m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$14=l\times 2$

$\frac{14}{2}=\frac{l\times 2}{2}$

7=l

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Example Question #64 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 16m^2 and a width of 8m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$16=l\times 8$

$\frac{16}{8}=\frac{l\times 8}{8}$

2=l

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Example Question #65 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 24m^2 and a width of 3m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$24=l\times 3$

$\frac{24}{3}=\frac{l\times 3}{3}$

8=l

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Example Question #66 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 28m^2 and a width of 14m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$28=l\times 14$

$\frac{28}{14}=\frac{l\times 14}{14}$

2=l

Report an Error

Example Question #67 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 30m^2 and a width of 3m?

Possible Answers:

10m

Correct answer:

10m

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$30=l\times 3$

$\frac{30}{3}=\frac{l\times 3}{3}$

10=l

Report an Error

Example Question #68 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 42m^2 and a width of 14m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$42=l\times 14$

$\frac{42}{14}=\frac{l\times 14}{14}$

3=l

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Example Question #121 : Parallelograms

What is the length of a rectangular yard with an area of 24m^2 and a width of 6m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$24=l\times 6$

$\frac{24}{6}=\frac{l\times 6}{6}$

4=l

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Example Question #122 : Parallelograms

What is the length of a rectangular yard with an area of 27m^2 and a width of 9m?

Possible Answers:

Correct answer:

Explanation:

$A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$27=l\times 9$

$\frac{27}{9}=\frac{l\times 9}{9}$

3=l

Report an Error

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All Common Core: 4th Grade Math Resources

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Common Core: 4th Grade Math : Solving for Length

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #61 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #62 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #63 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #64 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #65 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #66 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #67 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #68 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #121 : Parallelograms

Example Question #122 : Parallelograms

All Common Core: 4th Grade Math Resources

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