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Common Core: 6th Grade Math : Fluently Divide Multi-Digit Numbers: CCSS.Math.Content.6.NS.B.2

Study concepts, example questions & explanations for Common Core: 6th Grade Math

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All Common Core: 6th Grade Math Resources

6 Diagnostic Tests 186 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #111 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 9{\overline{\smash{)}369}}\\ -\ 36 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$9\times 29$

$9\times 52$

$9\times 31$

$9\times 37$

$9\times 41$

Correct answer:

$9\times 41$

Explanation:

The computation shows that $369\div9=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 9}{\overline{\smash{)}369}}\\ -\ 36 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$9\times41=369+0$

Simplify.

$9\times41=369$

The correct answer is $9\times 41$

Report an Error

Example Question #112 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 9{\overline{\smash{)}459}}\\ -\ 45 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$9\times 50$

$9\times 45$

$9\times 40$

$9\times 60$

$9\times 51$

Correct answer:

$9\times 51$

Explanation:

The computation shows that $459\div9=51$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 9}{\overline{\smash{)}459}}\\ -\ 45 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 9\ \ }\\ -\ \ \ 9\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$9\times51=459+0$

Simplify.

$9\times51=459$

The correct answer is $9\times 51$

Report an Error

Example Question #113 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 6{\overline{\smash{)}246}}\\ -\ 24 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{6\ \ }\\ -\ \ \ 6\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$6\times 21$

$6\times 36$

$6\times 32$

$6\times 41$

$6\times 31$

Correct answer:

$6\times 41$

Explanation:

The computation shows that $246\div6=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 6}{\overline{\smash{)}246}}\\ -\ 24 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 6\ \ }\\ -\ \ \ 6\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$6\times41=246+0$

Simplify.

$6\times41=246$

The correct answer is $6\times 41$

Report an Error

Example Question #114 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 21\\ 6{\overline{\smash{)}126}}\\ -\ 12 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{6\ \ }\\ -\ \ \ 6\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$6\times 36$

$6\times 32$

$6\times 21$

$6\times 42$

$6\times 31$

Correct answer:

$6\times 21$

Explanation:

The computation shows that $126\div6=21$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 21}\\ {\color{Green} 6}{\overline{\smash{)}126}}\\ -\ 12 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 6\ \ }\\ -\ \ \ 6\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$6\times21=126+0$

Simplify.

$6\times21=126$

The correct answer is $6\times 21$

Report an Error

Example Question #31 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 41\\ 4{\overline{\smash{)}164}}\\ -\ 16 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 16$

$4\times 41$

$4\times 12$

$4\times 31$

$4\times 51$

Correct answer:

$4\times 41$

Explanation:

The computation shows that $164\div4=41$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 41}\\ {\color{Green} 4}{\overline{\smash{)}164}}\\ -\ 16 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times41=164+0$

Simplify.

$4\times41=164$

The correct answer is $4\times 41$

Report an Error

Example Question #32 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 51\\ 4{\overline{\smash{)}204}}\\ -\ 20 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 41$

$4\times 51$

$4\times 20$

$4\times 61$

$4\times 24$

Correct answer:

$4\times 51$

Explanation:

The computation shows that $204\div4=51$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 51}\\ {\color{Green} 4}{\overline{\smash{)}204}}\\ -\ 20 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times51=204+0$

Simplify.

$4\times51=204$

The correct answer is $4\times 51$

Report an Error

Example Question #3742 : Numbers And Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 61\\ 4{\overline{\smash{)}244}}\\ -\ 24 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 71$

$4\times 42$

$4\times 61$

$4\times 31$

$4\times 24$

Correct answer:

$4\times 61$

Explanation:

The computation shows that $254\div4=61$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 61}\\ {\color{Green} 4}{\overline{\smash{)}244}}\\ -\ 24 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times61=244+0$

Simplify.

$4\times61=204$

The correct answer is $4\times 61$

Report an Error

Example Question #481 : How To Divide

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 71\\ 4{\overline{\smash{)}284}}\\ -\ 28 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 91$

$4\times 71$

$4\times 61$

$4\times 82$

$4\times 81$

Correct answer:

$4\times 71$

Explanation:

The computation shows that $284\div4=71$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 71}\\ {\color{Green} 4}{\overline{\smash{)}284}}\\ -\ 28 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times71=284+0$

Simplify.

$4\times71=284$

The correct answer is $4\times 71$

Report an Error

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 81\\ 4{\overline{\smash{)}324}}\\ -\ 32 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 32$

$4\times 81$

$4\times 91$

$4\times 82$

$4\times 101$

Correct answer:

$4\times 81$

Explanation:

The computation shows that $324\div4=81$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 4}{\overline{\smash{)}324}}\\ -\ 32 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times81=324+0$

Simplify.

$4\times81=324$

The correct answer is $4\times 81$

Report an Error

Example Question #121 : Grade 6

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 91\\ 4{\overline{\smash{)}364}}\\ -\ 36 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$4\times 91$

$4\times 36$

$4\times 63$

$4\times 81$

$4\times 101$

Correct answer:

$4\times 91$

Explanation:

The computation shows that $364\div4=91$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 91}\\ {\color{Green} 4}{\overline{\smash{)}364}}\\ -\ 36 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 4\ \ }\\ -\ \ \ 4\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$4\times91=364+0$

Simplify.

$4\times91=364$

The correct answer is $4\times 91$

Report an Error

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Common Core: 6th Grade Math : Fluently Divide Multi-Digit Numbers: CCSS.Math.Content.6.NS.B.2

Study concepts, example questions & explanations for Common Core: 6th Grade Math

All Common Core: 6th Grade Math Resources

Example Questions

Example Question #111 : Grade 6

Example Question #112 : Grade 6

Example Question #113 : Grade 6

Example Question #114 : Grade 6

Example Question #31 : The Number System

Example Question #32 : The Number System

Example Question #3742 : Numbers And Operations

Example Question #481 : How To Divide

Example Question #26 : Fluently Divide Multi Digit Numbers: Ccss.Math.Content.6.Ns.B.2

Example Question #121 : Grade 6

All Common Core: 6th Grade Math Resources

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