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Common Core: High School - Geometry : Circles

Study concepts, example questions & explanations for Common Core: High School - Geometry

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=25$ , and R=4 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{25}{4}$

R'=4

$R'=\frac{4}{25}$

R'=100

R'=25

Correct answer:

$R'=\frac{4}{25}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$25=\frac{4}{R'}$

Multiply by on each side.

25R'=4

Divide by to get .

$R'=\frac{4}{25}$

Report an Error

Example Question #1 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=118$ , and R=12 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

R'=6

$R'=\frac{1}{118}$

$R'=\frac{6}{59}$

R'=59

R'=118

Correct answer:

$R'=\frac{6}{59}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$118=\frac{12}{R'}$

Multiply by on each side.

118R'=12

Divide by 118 to get .

$R'=\frac{12}{118}=\frac{6}{59}$

Report an Error

Example Question #2 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=115$ , and R=9 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

R'=9

R'=106

$R'=\frac{9}{115}$

$R'=\frac{115}{9}$

R'=115

Correct answer:

$R'=\frac{9}{115}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$115=\frac{9}{R'}$

Multiply by on each side.

115R'=9

Divide by 115 to get .

$R'=\frac{9}{115}$

Report an Error

Example Question #4 : Circles

Given $\frac{C}{C'}=58$ , and R=6 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

R'=3

$R'=\frac{29}{3}$

$R'=\frac{3}{29}$

R'=58

R'=29

Correct answer:

$R'=\frac{3}{29}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$58=\frac{6}{R'}$

Multiply by on each side.

58R'=6

Divide by to get .

$R'=\frac{6}{58}=\frac{3}{29}$

Report an Error

Example Question #211 : High School: Geometry

Given $\frac{C}{C'}=55$ , and R=18 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{18}{55}$

$R'=\frac{1}{18}$

$R'=\frac{55}{18}$

R'=55

R'=18

Correct answer:

$R'=\frac{18}{55}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$55=\frac{18}{R'}$

Multiply by on each side.

55R'=18

Divide by to get .

$R'=\frac{18}{55}$

Report an Error

Example Question #3 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=113$ , and R=12 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{113}{12}$

$R'=\frac{1}{12}$

R'=12

R'=113

$R'=\frac{12}{113}$

Correct answer:

$R'=\frac{12}{113}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$113=\frac{12}{R'}$

Multiply by on each side.

113R'=12

Divide by 113 to get .

$R'=\frac{12}{113}$

Report an Error

Example Question #211 : High School: Geometry

Given $\frac{C}{C'}=113$ , and R=16 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{16}{113}$

$R'=\frac{113}{16}$

R'=16

$R'=\frac{1}{16}$

R'=113

Correct answer:

$R'=\frac{16}{113}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$113=\frac{16}{R'}$

Multiply by on each side.

113R'=16

Divide by 113 to get .

$R'=\frac{16}{113}$

Report an Error

Example Question #4 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=36$ , and R=8 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{2}{9}$

R'=36

R'=9

$R'=\frac{9}{2}$

R'=2

Correct answer:

$R'=\frac{2}{9}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$36=\frac{8}{R'}$

Multiply by on each side.

36R'=8

Divide by to get .

$R'=\frac{8}{36}=\frac{2}{9}$

Report an Error

Example Question #3 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=92$ , and R=5 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

R'=92

$R'=\frac{92}{5}$

R'=5

$R'=\frac{1}{92}$

$R'=\frac{5}{92}$

Correct answer:

$R'=\frac{5}{92}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$92=\frac{5}{R'}$

Multiply by on each side.

92R'=5

Divide by to get .

$R'=\frac{5}{92}$

Report an Error

Example Question #5 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Given $\frac{C}{C'}=76$ , and R=6 , what is R'?

Screen shot 2020 07 01 at 7.06.26 pm

Possible Answers:

$R'=\frac{38}{3}$

R'=3

$R'=\frac{3}{38}$

$R'=\frac{1}{38}$

R'=38

Correct answer:

$R'=\frac{3}{38}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$76=\frac{6}{R'}$

Multiply by on each side.

76R'=6

Divide by to get .

$R'=\frac{6}{76}=\frac{3}{38}$

Report an Error

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All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: High School - Geometry : Circles

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #1 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #1 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #2 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #4 : Circles

Example Question #211 : High School: Geometry

Example Question #3 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #211 : High School: Geometry

Example Question #4 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #3 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

Example Question #5 : Similar Circles: Ccss.Math.Content.Hsg C.A.1

All Common Core: High School - Geometry Resources

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