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GED Math : GED Math

Study concepts, example questions & explanations for GED Math

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All GED Math Resources

4 Diagnostic Tests 263 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #113 : Algebra

Solve for : 3y-7 = 4y

Possible Answers:

$-\frac{7}{12}$

Correct answer:

Explanation:

Subtract from both sides.

3y-7-3y = 4y-3y

Simplify both sides.

-7 =y

The answer is:

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Example Question #112 : Algebra

Solve for : $\frac{1}{2}x +\frac{7}{3} = \frac{8}{3}$

Possible Answers:

$\textup{The answer is not given.}$

$\frac{1}{6}$

$\frac{2}{3}$

Correct answer:

$\frac{2}{3}$

Explanation:

Multiply both sides by the least common denominator to cancel out the fractions.

$6(\frac{1}{2}x +\frac{7}{3}) = \frac{8}{3}\cdot6$

3x+14 = 16

Subtract 14 on both sides.

3x+14 -14= 16-14

3x=2

Divide by 3 on both sides.

$\frac{3x}{3}=\frac{2}{3}$

The answer is: $\frac{2}{3}$

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Example Question #673 : Ged Math

Given the following equation, find the value of b when w=-3

$b-2=\frac{5w+12}{3}+4$

Possible Answers:

Correct answer:

Explanation:

Given the following equation, find the value of b when w=-3

$b-2=\frac{5w+12}{3}+4$

This may look a little messy up front, but don't worry, it's not overly complicated.

All we need to do is plug in -3 for w and solve for b.

Let's begin:

$b-2=\frac{5(-3)+12}{3}+4$

$b-2=\frac{-15+12}{3}+4$

Now add our numbers:

$b-2=\frac{-3}{3}+4$

Now we can simplify our fraction to get:

b-2=-1+4

From her on out it is just subtraction and addition:

b-2=3

b=3+2=5

So our answer is 5

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Example Question #674 : Ged Math

Solve for .

$\sqrt{3x+4}-2=6$

Possible Answers:

Correct answer:

Explanation:

$\sqrt{3x+4}-2=6$

Start by adding to both sides.

$\sqrt{3x+4}=8$

Next, square both sides to get rid of the square root.

3x+4=64

Subtract from both sides.

3x=60

Finally, divide both sides by .

x=20

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Example Question #113 : Algebra

Solve for :

$\sqrt{3x-1}+5=9$

Possible Answers:

$\frac{17}{3}$

$\frac{3}{17}$

Correct answer:

$\frac{17}{3}$

Explanation:

$\sqrt{3x-1}+5=9$

Start by subtracting from both sides.

$\sqrt{3x-1}=4$

Now, square both sides of the equation to get rid of the square root.

3x-1=16

Add to both sides.

3x=17

Divide both sides by .

$x=\frac{17}{3}$

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Example Question #71 : Solving For The Variable

Solve for .

$\sqrt{x+15}-2=4$

Possible Answers:

x=21

x=26

x=41

x=16

Correct answer:

x=21

Explanation:

$\sqrt{x+15}-2=4$

Start by adding to both sides.

$\sqrt{x+15}=6$

Next, square both sides to get rid of the square root.

x+15=36

Finally, subtract from both sides.

x=21

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Example Question #71 : Solving For The Variable

Solve for $\small x$ : $\small x=7+5-2$

Possible Answers:

$\small x=12$

$\small x=10$

None of these answers

$\small x=13$

$\small x=11$

Correct answer:

$\small x=10$

Explanation:

To solve for $\small x$ , all you have to do is simplify your equation until you get a number on one side and your $\small x$ on the other.

So for starters we already have all of our numbers on one side: $\small x=7+5-2$ . Now all we need to do is add and subtract when called for in order to get our answer.

Start by adding $\small 7$ to $\small 5$

$\small x=(7+5)-2$

$\small x=12-2$

Now subtract $\small 2$ from our newly formed $\small 12$

$\small x=10$

Your answer is $\small x=10$

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Example Question #72 : Solving For The Variable

Solve for $\small x$ : $\small x-6=5\cdot3$

Possible Answers:

$\small x=21$

None of the other answers

$\small x=20$

$\small x=23$

$\small x=18$

Correct answer:

$\small x=21$

Explanation:

In order to solve for $\small x$ , all you have to do is simplify your equation so that your $\small x$ is on one side and your number is on the other.

For this equation, we have one number accompanying our $\small x$ . That is $\small -6$ : $\small x-6=5\cdot3$ .

Let's move that $\small -6$ over to the other side by adding it on both sides.

$\small x=5\cdot3-6$

Now that all of our numbers are on one side, it's time to simplify. Multiplication comes before addition, so we need to multiply the $\small 5$ and $\small 3$ together before we touch the $\small 6$ .

$\small x=(5\cdot 3)-6$

$\small x=15-6$

Now we can add the $\small 6$ to $\small 15$ .

$\small x=21$

Our answer is $\small x=21$

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Example Question #122 : Algebra

Solve for $\small x$ : $\small \frac{x+6}{2}=6$

Possible Answers:

None of the other answers

$\small x=8$

$\small x=0$

$\small x=12$

$\small x=6$

Correct answer:

$\small x=6$

Explanation:

In order to solve for $\small x$ , we must simplify our equation so that we have $\small x$ on one side and our final number on the other side.

Before we can do any simplifying, we must get $\small x$ by itself. Currently our $\small x$ is being added by $\small 6$ , but it's also being divided by $\small 2$ . We can't touch the $\small +6$ yet, so let's move the $\small 2$ by multiplying both sides.

$\small \frac{x+6}{2}=6$

$\small x+6=6\cdot2$

Now let's move that $\small 6$ on the $\small x$ side by subtracting it on both sides.

$\small x+6=6\cdot2$

$\small x=6\cdot2-6$

Now that we have all our numbers to one side, it's time to start simplifying. Multiplication comes before subtraction, so we're going to multiply our $\small 6$ and $\small 2$ together.

$\small x=(6\cdot 2)-6$

$\small x=12-6$

Now we can subtract our $\small 6$ from $\small 12$ .

$\small x=12-6$

$\small x=6$

Our answer is $\small x=6$

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Example Question #71 : Solving For The Variable

6x- 17 = 3x

Evaluate .

Possible Answers:

$x= 3 \frac{2}{3}$

$x = 1\frac{8}{9}$

$x = 2\frac{1}{3}$

$x= 5\frac{2}{3}$

Correct answer:

$x= 5\frac{2}{3}$

Explanation:

Solve this equation for by isolating the on the left side of the equation. This can be done by first, subtracting from both sides:

6x- 17 = 3x

6x- 17- 3x = 3x - 3x

6x- 3x - 17 =0

Collect like terms by subtracting coefficients of :

(6-3)x-17=0

3x - 17 =0

Add 17 to both sides:

3x - 17+ 17 =0+ 17

3x= 17

Divide both sides by 3:

$3x \div 3= 17 \div 3$

$x = \frac{17}{3}= 5 \frac{2}{3}$ ,

the correct choice.

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All GED Math Resources

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GED Math : GED Math

Study concepts, example questions & explanations for GED Math

All GED Math Resources

Example Questions

Example Question #113 : Algebra

Example Question #112 : Algebra

Example Question #673 : Ged Math

Example Question #674 : Ged Math

Example Question #113 : Algebra

Example Question #71 : Solving For The Variable

Example Question #71 : Solving For The Variable

Example Question #72 : Solving For The Variable

Example Question #122 : Algebra

Example Question #71 : Solving For The Variable

All GED Math Resources

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