High School Math : Integers

Study concepts, example questions & explanations for High School Math

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Example Questions

Example Question #11 : Integers

Find the difference. 

 

\(\displaystyle (-5) - 2 =\) 

Possible Answers:

\(\displaystyle -7\)

\(\displaystyle -3\)

\(\displaystyle 10\)

\(\displaystyle 3\)

\(\displaystyle 7\)

Correct answer:

\(\displaystyle -7\)

Explanation:

We are subtracting here, so it is important to remember that subtracting is really just adding the same number with opposite sign. Thus we can think of the problem as the following: 

\(\displaystyle (-5) + (-2)\), which we know is equal to \(\displaystyle -7\).

Example Question #12 : Integers

What is \(\displaystyle 10 - (-2)\) ? 

Possible Answers:

\(\displaystyle -12\)

\(\displaystyle 12\)

\(\displaystyle -8\)

\(\displaystyle 8\)

\(\displaystyle 14\)

Correct answer:

\(\displaystyle 12\)

Explanation:

Recall that subtracting integers is equivalent to adding the inverse. The inverse of a negative number is the positive number with the same magnitude.

Thus, our problem is equivalent to \(\displaystyle 10 + 2 = 12\).

Example Question #13 : Integers

Evaluate the following expression: 

\(\displaystyle -2 - (-4)\)

Possible Answers:

\(\displaystyle 2\)

\(\displaystyle -6\)

\(\displaystyle -2\)

\(\displaystyle 8\)

\(\displaystyle 6\)

Correct answer:

\(\displaystyle 2\)

Explanation:

Recall that subtracting is equivalent to adding the inverse:

\(\displaystyle -2 - (-4) = -2 + (-(-4))\)

The inverse of a negative number is a positive number:

\(\displaystyle -2 - (-4) = -2 + 4 = 2\)

Example Question #66 : High School Math

What is: 

\(\displaystyle -4 + 8\)

Possible Answers:

\(\displaystyle -4\)

\(\displaystyle 12\)

\(\displaystyle 4\)

\(\displaystyle -12\)

\(\displaystyle 16\)

Correct answer:

\(\displaystyle 4\)

Explanation:

Recall the placement of numbers on the number line. \(\displaystyle -4\) is \(\displaystyle 4\) spaces to the left of \(\displaystyle 0\), and then we add \(\displaystyle 8\), resulting in movement to the right. 

When we add these spaces we end up going \(\displaystyle 4\) spaces back to \(\displaystyle 0\) and then \(\displaystyle 4\) additional spaces to end at \(\displaystyle 4\)

Example Question #14 : Integers

What is \(\displaystyle 8 - (-3)\) ? 

Possible Answers:

\(\displaystyle -11\)

\(\displaystyle 33\)

\(\displaystyle 5\)

\(\displaystyle -5\)

\(\displaystyle 11\)

Correct answer:

\(\displaystyle 11\)

Explanation:

Recall that subtracting a negative number is equivalent to adding the opposite. Thus, \(\displaystyle 8 - (-3) = 8 + 3 = 11\)

Example Question #15 : Integers

What is \(\displaystyle -3 - (-5)\)

Possible Answers:

\(\displaystyle -8\)

\(\displaystyle 8\)

\(\displaystyle -2\)

\(\displaystyle 2\)

\(\displaystyle 15\)

Correct answer:

\(\displaystyle 2\)

Explanation:

Recall that subtracting negative numbers is equivalent to adding the opposite. Then, we have that: 

\(\displaystyle -3 - (-5) = -3 + 5 = 2\)

Example Question #1 : How To Multiply And Divide Integers In Pre Algebra

Solve the expression below.

\(\displaystyle -5*-3\)

Possible Answers:

\(\displaystyle 15\)

\(\displaystyle -15\)

\(\displaystyle -8\)

\(\displaystyle 8\)

\(\displaystyle 25\)

Correct answer:

\(\displaystyle 15\)

Explanation:

In this case, it is key to recall the rules for multiplying or dividing with negative values.

Negative * Positive = Negative

Negative * Negative = Positive

Positive * Positive = Positive

In this case, we are multiplying two negative numbers; thus the answer should be a positive number. To find the value, we can simply multiply the terms without their negatives.

\(\displaystyle -5*-3=5*3=15\)

Example Question #67 : High School Math

Simplify:

\(\displaystyle (-2y)(3)(-5y)\)

 

Possible Answers:

\(\displaystyle 30y\)

\(\displaystyle 21y^2\)

\(\displaystyle 30y^2\)

\(\displaystyle -21y^2\)

\(\displaystyle -30y^2\)

Correct answer:

\(\displaystyle 30y^2\)

Explanation:

First multiply all the numbers \(\displaystyle (2 \cdot 3 \cdot 5)\).

If there is an even amount of negative signs, then the product will be positive. If there is an odd amount of negative signs, then the product will be negative.

\(\displaystyle y\cdot y=y^{2}\)

Therefore, the answer is \(\displaystyle 30y^2\).  

Example Question #2 : How To Multiply And Divide Integers In Pre Algebra

Combine like terms for the simplest form:

\(\displaystyle 2x*3y-2y+3x=0\)

Possible Answers:

\(\displaystyle 6x*y=0\)

\(\displaystyle 2x*3y-2y+3x=0\)

\(\displaystyle 6xy-5xy=0\)

\(\displaystyle 6xy=0\)

\(\displaystyle 6xy-2y+3x=0\)

Correct answer:

\(\displaystyle 6xy-2y+3x=0\)

Explanation:

First multiply according to order of operations to get 6xy, and then see if there are like terms to be combined. In this case, there are not so the simplest form is \(\displaystyle 2x*3y-2y+3x=0\)

Example Question #3 : How To Multiply And Divide Integers In Pre Algebra

All of the following numbers are prime EXCEPT:

Possible Answers:

421

401

347

427

349

Correct answer:

427

Explanation:

A number is prime if it is divisible by only itself and one. Thus, if a number is divisible by anything else, it can't be prime. Of the answer choices, only 427 isn't prime, because it is divisible by 7.

To figure out which number is prime, one strategy you could employ is using your calculator and dividing each choice by 3, 7, 9, 11, and 13. Because all of the answer choices are odd, we know none of them will be divisible by 2, 4, 6, 8, or 10. Also, none of them have a 0 or 5 in the ones place, so they can't be divisible by 5. Thus, the best numbers to try would be 3, 7, 9, 11, and 13. When you divide 427 by 7, you will get a whole number. For all the other answer choices, when you divide by 3, 7, 9, 11, and 13, you will never get a whole number.

The answer is 427.

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