Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Middle Level Math : Geometry

Study concepts, example questions & explanations for ISEE Middle Level Math

Create An Account

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1963 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Find the area of a square with a base of length 8 inches.

Possible Answers:

$32\text{in}^2$ $\displaystyle 32\text{in}^2$

$16\text{in}^2$ $\displaystyle 16\text{in}^2$

$64\text{in}^2$ $\displaystyle 64\text{in}^2$

$32\text{in}$ $\displaystyle 32\text{in}$

$64\text{in}$ $\displaystyle 64\text{in}$

Correct answer:

$64\text{in}^2$ $\displaystyle 64\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the base has a length of 8 inches. Because it is a square, we know that all sides are equal. Therefore, all sides have a length of 8 inches. This means the width is also 8 inches. Knowing this, we can substitute into the formula. We get

$\text{area of square} = 8\text{in} \cdot 8\text{in}$ $\displaystyle \text{area of square} = 8\text{in} \cdot 8\text{in}$

$\text{area of square} = 64\text{in}^2$ $\displaystyle \text{area of square} = 64\text{in}^2$

Report an Error

Example Question #43 : Squares

Find the area of a square with a base of 12 inches.

Possible Answers:

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

$144\text{in}^2$ $\displaystyle 144\text{in}^2$

$48\text{in}$ $\displaystyle 48\text{in}$

$\text{There is not enough information to solve the problem.}$ $\displaystyle \text{There is not enough information to solve the problem.}$

$144\text{in}$ $\displaystyle 144\text{in}$

Correct answer:

$144\text{in}^2$ $\displaystyle 144\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the base of the square is 12in. Because it is a square, we know that all sides are equal. Which means all sides are 12in. Therefore, the width is also 12in. Knowing this, we can substitute into the formula. We get

$\text{area of square} = 12\text{in} \cdot 12\text{in}$ $\displaystyle \text{area of square} = 12\text{in} \cdot 12\text{in}$

$\text{area of square} = 144\text{in}^2$ $\displaystyle \text{area of square} = 144\text{in}^2$

Report an Error

Example Question #1964 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Find the area of a square with a width of 5 feet.

Possible Answers:

$15\text{ft}^2$ $\displaystyle 15\text{ft}^2$

$\text{There is not enough information to solve the problem.}$ $\displaystyle \text{There is not enough information to solve the problem.}$

$10\text{ft}^2$ $\displaystyle 10\text{ft}^2$

$20\text{ft}^2$ $\displaystyle 20\text{ft}^2$

$25\text{ft}^2$ $\displaystyle 25\text{ft}^2$

Correct answer:

$25\text{ft}^2$ $\displaystyle 25\text{ft}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width is 5 feet. Because it is a square, all sides are equal. This means the length is also 5 feet.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 5\text{ft} \cdot 5\text{ft}$ $\displaystyle \text{area of square} = 5\text{ft} \cdot 5\text{ft}$

$\text{area of square} = 25\text{ft}^2$ $\displaystyle \text{area of square} = 25\text{ft}^2$

Report an Error

Example Question #44 : Squares

Find the area of a square with a width of 12cm.

Possible Answers:

$24\text{cm}^2$ $\displaystyle 24\text{cm}^2$

$144\text{cm}^2$ $\displaystyle 144\text{cm}^2$

$48\text{cm}^2$ $\displaystyle 48\text{cm}^2$

$121\text{cm}^2$ $\displaystyle 121\text{cm}^2$

$96\text{cm}^2$ $\displaystyle 96\text{cm}^2$

Correct answer:

$144\text{cm}^2$ $\displaystyle 144\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 12cm. Because it is a square, all sides are equal. Therefore, the length is also 12cm.

Knowing this, we will substitute into the formula. We get

$\text{area of square} = 12\text{cm} \cdot 12\text{cm}$ $\displaystyle \text{area of square} = 12\text{cm} \cdot 12\text{cm}$

$\text{area of square} = 144\text{cm}^2$ $\displaystyle \text{area of square} = 144\text{cm}^2$

Report an Error

Example Question #48 : Quadrilaterals

Use the following image to answer the question:

Square3

Find the area of the square.

Possible Answers:

$24\text{cm}^2$ $\displaystyle 24\text{cm}^2$

$\text{There is not enough information to solve the problem.}$ $\displaystyle \text{There is not enough information to solve the problem.}$

$32\text{cm}^2$ $\displaystyle 32\text{cm}^2$

$16\text{cm}^2$ $\displaystyle 16\text{cm}^2$

$64\text{cm}^2$ $\displaystyle 64\text{cm}^2$

Correct answer:

$64\text{cm}^2$ $\displaystyle 64\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, let's look at the given square.

Square3

We can see the width is 8cm. Because it is a square, we know that all sides are equal. Therefore, the width is also 8cm.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 8\text{cm} \cdot 8\text{cm}$ $\displaystyle \text{area of square} = 8\text{cm} \cdot 8\text{cm}$

$\text{area of square} = 64\text{cm}^2$ $\displaystyle \text{area of square} = 64\text{cm}^2$

Report an Error

Example Question #41 : Squares

Find the area of a square with a length of 11in.

Possible Answers:

$121\text{in}^2$ $\displaystyle 121\text{in}^2$

$100\text{in}^2$ $\displaystyle 100\text{in}^2$

$\text{There is not enough information to solve the problem.}$ $\displaystyle \text{There is not enough information to solve the problem.}$

$22\text{in}^2$ $\displaystyle 22\text{in}^2$

$44\text{in}^2$ $\displaystyle 44\text{in}^2$

Correct answer:

$121\text{in}^2$ $\displaystyle 121\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the length of the square is 11in. Because it is a square, all sides are equal. Therefore, the width is also 11in.

Knowing this, we will substitute into the formula. We get

$\text{area of square} = 11\text{in} \cdot 11\text{in}$ $\displaystyle \text{area of square} = 11\text{in} \cdot 11\text{in}$

$\text{area of square} = 121\text{in}^2$ $\displaystyle \text{area of square} = 121\text{in}^2$

Report an Error

Example Question #141 : Plane Geometry

Use the following square to answer the question:

Square2

Find the area.

Possible Answers:

$196\text{cm}^2$ $\displaystyle 196\text{cm}^2$

$28\text{cm}^2$ $\displaystyle 28\text{cm}^2$

$56\text{cm}^2$ $\displaystyle 56\text{cm}^2$

$108\text{cm}^2$ $\displaystyle 108\text{cm}^2$

$\text{There is not enough information to solve the problem.}$ $\displaystyle \text{There is not enough information to solve the problem.}$

Correct answer:

$196\text{cm}^2$ $\displaystyle 196\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, given the square

Square2

we can see the length is 14cm. Because it is a square, all sides are equal. Therefore, the width is also 14cm.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 14\text{cm} \cdot 14\text{cm}$ $\displaystyle \text{area of square} = 14\text{cm} \cdot 14\text{cm}$

$\text{area of square} = 196\text{cm}^2$ $\displaystyle \text{area of square} = 196\text{cm}^2$

Report an Error

Example Question #142 : Plane Geometry

Find the area of a square with a length of 8in.

Possible Answers:

$56\text{in}^2$ $\displaystyle 56\text{in}^2$

$24\text{in}^2$ $\displaystyle 24\text{in}^2$

$72\text{in}^2$ $\displaystyle 72\text{in}^2$

$64\text{in}^2$ $\displaystyle 64\text{in}^2$

$32\text{in}^2$ $\displaystyle 32\text{in}^2$

Correct answer:

$64\text{in}^2$ $\displaystyle 64\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

So, we know the length of the square is 8in. Because it is a square, all sides are equal. Therefore, the width is also 8in.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 8\text{in} \cdot 8\text{in}$ $\displaystyle \text{area of square} = 8\text{in} \cdot 8\text{in}$

$\text{area of square} = 64\text{in}^2$ $\displaystyle \text{area of square} = 64\text{in}^2$

Report an Error

Example Question #143 : Plane Geometry

Find the area of a square that has a width of 15in.

Possible Answers:

$125\text{in}^2$ $\displaystyle 125\text{in}^2$

$60\text{in}^2$ $\displaystyle 60\text{in}^2$

$225\text{in}^2$ $\displaystyle 225\text{in}^2$

$45\text{in}^2$ $\displaystyle 45\text{in}^2$

$30\text{in}^2$ $\displaystyle 30\text{in}^2$

Correct answer:

$225\text{in}^2$ $\displaystyle 225\text{in}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the width of the square is 15in. Because it is a square, all sides are equal. Therefore, the length is also 15in.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 15\text{in} \cdot 15\text{in}$ $\displaystyle \text{area of square} = 15\text{in} \cdot 15\text{in}$

$\text{area of square} = 225\text{in}^2$ $\displaystyle \text{area of square} = 225\text{in}^2$

Report an Error

Example Question #144 : Plane Geometry

Find the area of a square with a base of 18cm.

Possible Answers:

$72\text{cm}^2$ $\displaystyle 72\text{cm}^2$

$324\text{cm}^2$ $\displaystyle 324\text{cm}^2$

$36\text{cm}^2$ $\displaystyle 36\text{cm}^2$

$124\text{cm}^2$ $\displaystyle 124\text{cm}^2$

$248\text{cm}^2$ $\displaystyle 248\text{cm}^2$

Correct answer:

$324\text{cm}^2$ $\displaystyle 324\text{cm}^2$

Explanation:

To find the area of a square, we will use the following formula:

$\text{area of square} = l \cdot w$ $\displaystyle \text{area of square} = l \cdot w$

where l is the length and w is the width of the square.

Now, we know the base of the square is 18cm. Because it is a square, all sides are equal. Therefore, the length is also 18cm.

Knowing this, we can substitute into the formula. We get

$\text{area of square} = 18\text{cm} \cdot 18\text{cm}$ $\displaystyle \text{area of square} = 18\text{cm} \cdot 18\text{cm}$

$\text{area of square} = 324\text{cm}^2$ $\displaystyle \text{area of square} = 324\text{cm}^2$

Report an Error

View Tutors

Clarissa
Certified Tutor

University of North Texas, Bachelor in Arts, International Relations.

View Tutors

Cheryl
Certified Tutor

Palm Beach Atlantic University-West Palm Beach, Bachelor of Science, Business Administration and Management. Southern New Ham...

View Tutors

Iffy
Certified Tutor

University of Maryland-Baltimore County, Bachelor of Science, Computer Engineering, General. University of Maryland-College P...

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

LSAT Tutors in San Diego, Physics Tutors in Dallas Fort Worth, GRE Tutors in Los Angeles, Physics Tutors in Washington DC, Computer Science Tutors in Houston, Physics Tutors in Miami, MCAT Tutors in San Diego, Chemistry Tutors in Dallas Fort Worth, Calculus Tutors in Boston, MCAT Tutors in Denver

Popular Courses & Classes

MCAT Courses & Classes in Atlanta, GRE Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Philadelphia, LSAT Courses & Classes in Los Angeles, ISEE Courses & Classes in Atlanta, LSAT Courses & Classes in San Francisco-Bay Area, GRE Courses & Classes in Washington DC, LSAT Courses & Classes in Boston, SSAT Courses & Classes in Los Angeles

Popular Test Prep

GMAT Test Prep in San Diego, GRE Test Prep in Houston, SSAT Test Prep in Philadelphia, GRE Test Prep in Dallas Fort Worth, ISEE Test Prep in Los Angeles, LSAT Test Prep in Seattle, GMAT Test Prep in Phoenix, SSAT Test Prep in New York City, MCAT Test Prep in Dallas Fort Worth, LSAT Test Prep in Boston

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Middle Level Math : Geometry

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #1963 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Example Question #43 : Squares

Example Question #1964 : Isee Middle Level (Grades 7 8) Mathematics Achievement

Example Question #44 : Squares

Example Question #48 : Quadrilaterals

Example Question #41 : Squares

Example Question #141 : Plane Geometry

Example Question #142 : Plane Geometry

Example Question #143 : Plane Geometry

Example Question #144 : Plane Geometry

All ISEE Middle Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: