MCAT Biology : Biology

Study concepts, example questions & explanations for MCAT Biology

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Example Questions

Example Question #55 : Genetics

In a dihybrid cross, what fraction of offspring will be homozygous for both traits?

Possible Answers:

Correct answer:

Explanation:

A dihybrid cross has two genes that have two alleles: Aa and Bb. In order for the progeny to be homozygous for both alleles, both genes need to have two copies of the same allele. As a result, there are four possible genotypes that allow the offspring to be homozygous for both genes at the same time: AABB, AAbb, aaBB, and aabb. This means that there are four out of sixteen variations that will result in a homozygous organism.

Example Question #54 : Cell Biology, Molecular Biology, And Genetics

Passage:

This has seemed a fatal objection to the chromosome view, but it may not be so, as Spillman has argued, so long as it has not yet been shown that all of the dominant characters may be present at the same time. But even admitting this possible way of eluding the objection, the other point raised above concerning the absence of groupings of characters in Mendelian inheritance seems a fatal objection to the chromosome theory, so long as that theory attempts to locate each character in a special chromosome. We shall have occasion to return to this point later.

In recent years most workers in Mendelian inheritance have adopted a new method of formulating their theory. Characters that Mendelize are no longer allelomorphic to each other, but each character has for its pair the absence of that character. This is the presence and absence theory. We can apply this hypothesis to the chromosome theory. For examples, let us assume a new variety or race arises by the loss of a character from that chromosome that has heretofore carried it. The chromosome still remains in existence, since it may carry many other characters besides the one that was lost, and it becomes in the hybrid the mate of the one still retaining that character. If now separation occurs, two classes of germ-cells result, one with and the other without the character; and the observed numerical proportions follow. There is nothing in this assumption that meets with any greater difficulty on the chromosome separation hypothesis than on the earlier view of paired allelomorphs, but it meets with the same difficulties, and as an assumption is neither more nor less in accord with the postulated mechanism.

Excerpt from Morgan, T. H. 1910. Chromosomes and heredity. The American Naturalist, 44:449–496.

 

Asssume that in a particular studied species of rodents, coat color is an autosomally-inherited trait, with black fur being the dominant phenotype and white fur being the recessive phenotype. In an experiment, a mouse with black fur mates with a mouse with a mouse with white fur. The resultant 26 offspring mice all have grey fur color. Which of the following genetic principles is best demonstrated by this result?

Possible Answers:

Nondisjunction

X-linkage

Spontaneous mutation

Incomplete Dominance

Codominance

Correct answer:

Incomplete Dominance

Explanation:

The genetic principle best demonstrated here is incomplete dominance. Incomplete dominance means that if a given trait has two alleles, neither allele is individually dominant to the other allele, and therefore, if an organism is heterozygous for that trait, it will display a phenotype that is intermediate between that coded for by each individual alleles. 

In this case, the parent mice are most likely BB (black fur) and bb (white fur), therefore homozygotes for fur color. As a result, any offspring that they have, will have genotype Bb. If this trait was inherited in such a manner that black fur was completely dominant to white fur, or vice versa, the mice would have either one of those fur colors in the progeny. Because the resulting fur color is grey, which is intermediate between black and white, this is evidence that the genetic principle at play here is incomplete dominance. 

Co-dominance is not the correct answer because a heterozygote for a co-dominant trait would demonstrate both phenotypes simultaneously (e.g. black and white fur color), rather than a blending of the individual phenotypes (e.g. grey fur color) as in these mice. 

X-linkage of fur color would not describe the presence of an intermediate phenotype, nor would nondisjunction. 

Spontaneous mutation could, in theory, result in a phenotype different from that of the parent mice. However, given that the resultant phenotype for the progeny mice was intermediate to that of the parents' fur colors, and the fact that all progeny demonstrated this phenotype, rather than just one or two mice, this is a more compelling demonstration of incomplete dominance. 

Example Question #53 : Genetics

How does meiosis incorporate genetic variation into the creation of haploid cells? 

Possible Answers:

The exchange of DNA sequences during prophase I

Crossing over in somatic cells

The random separation of entire tetrads during anaphase I

The deletion and addition of certain DNA sequences in telophase I

Correct answer:

The exchange of DNA sequences during prophase I

Explanation:

Meiosis only takes place in germ cells and is used to make haploid cells. In order to be genetically unique, chromosomes will exchange DNA sequences in a process called crossing over. This process of exchanging genetic material takes place during prophase I. Somatic cells are never involved in meiosis or crossing over, and DNA will never be deleted or added from the genome. Though separation of tetrads occurs during anaphase I and follows the law of independent assortment, the entire tetrad does not remain joined. This would result in nondisjunction.

Example Question #56 : Genetics

Which of the following statements are true about the significance of meiosis?

I. Enhances genetic variation

II. Maintains ploidy in sexually reproducing organisms

III. Allows for the potential repair of damaged DNA

Possible Answers:

I and II

I only

II and III

I, II, and III

Correct answer:

I, II, and III

Explanation:

All of the answers describe the diverse purposes of meiosis. Genetic variation is enhanced through the process of recombination and the separation of homologous chromosomes. Maintenance of ploidy in sexually reproducing organisms is achieved because gametes contain exactly half the number of chromosomes present in the mature organism. During fertilization, a gamete from a male and a gamete from a female combine and the result is a cell of normal ploidy. Meiosis also allows the cell an opportunity to repair damaged DNA via recombination between homologous chromosomes.

Example Question #52 : Genetics

Cellular division is an essential part of the cell cycle. When a cell divides it passes genetic information to daughter cells. The amount of genetic information passed on to daughter cells depends on whether the cell undergoes mitosis or meiosis. Mitosis is the most common form of cell division. All somatic cells undergo mitosis, whereas only germ cells undergo meiosis. Meiosis is very important because it produces gametes (sperm and eggs) that are required for sexual reproduction. Human germ cells have 46 chromosomes (2n = 46) and undergo meiosis to produce four haploid daughter cells (gametes).

A couple has ten children that look very different from one another. This phenomenon can be attributed to which of the following?

Possible Answers:

Crossing over

Cell differentiation

Ploidy of the gametes

Independent assortment

Correct answer:

Crossing over

Explanation:

One of the key characteristics of sexual reproduction is that it involves recombination. Recombination is the process by which genetic material is exchanged between chromosomes to create new alleles. This leads to innumerable possibilities for an offspring and is the reason why a couple can have ten unique children.

Recombination in meiosis occurs during prophase I. In prophase I genetic material between homologous chromosomes is exchanged in a process called crossing over. This exchange between genetic material leads to the ten children with different appearances.

Independent assortment helps explain why the offspring may not resemble the parent, but does less to explain why they do not resemble each other. During independent assortment, the homologous pairs are separated randomly such that a unique combination of maternal and paternal alleles are present in each cell after meiosis I. This can result in the expression of recessive alleles in the offspring that were not expressed in either parent.

Example Question #1124 : Mcat Biological Sciences

Which of the following is inherited via an autosomal recessive allele?

Possible Answers:

Hemophilia

Color-blindness

Huntington's disease

Cystic fibrosis

Correct answer:

Cystic fibrosis

Explanation:

Of the given answer options, only cystic fibrosis is inherited via an autosomal recessive inheritance pattern. Color-blindness and hemophilia are both X-linked recessive disorders. Huntington's disease is an autosomal dominant disorder.

Example Question #61 : Genetics

45 map units equals approximately what percent chance of recombination?

Possible Answers:

Not enough information is given.

0%

55%

45%

90%

Correct answer:

45%

Explanation:

1 map unit equals 1% chance of recombination; therefore, 45% is the best answer.

Example Question #61 : Cell Biology, Molecular Biology, And Genetics

Scientists use a process called Flourescent In-Situ Hybridization, or FISH, to study genetic disorders in humans. FISH is a technique that uses spectrographic analysis to determine the presence or absence, as well as the relative abundance, of genetic material in human cells. 

To use FISH, scientists apply fluorescently-labeled bits of DNA of a known color, called probes, to samples of test DNA. These probes anneal to the sample DNA, and scientists can read the colors that result using laboratory equipment. One common use of FISH is to determine the presence of extra DNA in conditions of aneuploidy, a state in which a human cell has an abnormal number of chromosomes. Chromosomes are collections of DNA, the totality of which makes up a cell’s genome. Another typical use is in the study of cancer cells, where scientists use FISH labels to ascertain if genes have moved inappropriately in a cell’s genome.

Using red fluorescent tags, scientists label probe DNA for a gene known to be expressed more heavily in cancer cells than normal cells. They then label a probe for an immediately adjacent DNA sequence with a green fluorescent tag. Both probes are then added to three dishes, shown below.  In dish 1 human bladder cells are incubated with the probes, in dish 2 human epithelial cells are incubated, and in dish 3 known non-cancerous cells are used. The relative luminescence observed in regions of interest in all dishes is shown below.

 

Untitled

Which of the following genetic changes would not be detectable using FISH?

Possible Answers:

Unbalanced translocation

Robertsonian translocation

Copy number variant

Balanced translocation

Single nucleotide polymorphism

Correct answer:

Single nucleotide polymorphism

Explanation:

FISH is useful for visualizing major changes in the genome, as described by the passage. Translocations and large copy number variants would likley be visible in color changes, while small single nucleotide polymorphisms (SNPs) would likely be less easily detected.

Example Question #1101 : Biology

Which of the following represents a frameshift mutation to the given template strand?

5'-AGCCTTAGC-3'

Possible Answers:

5'-CTTAGC-3'

5'-AGCCTTAGG-3'

5'-TGCCTTAGC-3'

5'-AGCGCTTAGC-3'

5'-TTTAGCCTTAGC-3'

Correct answer:

5'-AGCGCTTAGC-3'

Explanation:

A frameshift mutation results in a change of the codon reading frame and results from the addition or deletion of a set of nucleotides that is not a multiple of three. If a mutation occurs that is a multiple of three, the reading frame is unchanged and a simple addition or deletion has occurred.

Template:               5'-AGC-CTT-AGC-3' 

Frameshift mutant:  5'-AGC-GCT-TAG-C-3' 

Point mutant:          5'-TGC-CTT-AGC-3'

Point mutant:          5'-AGC-CTT-AGG-3'

Deletion:                5'-CTT-AGC-3'

Insertion:               5'-TTT-AGC-CTT-AGC-3'

Note that all except the frameshift mutation contain sets of three nucleotides to create triplets. The frameshift leaves a singular, un-grouped cytosine.

Example Question #1132 : Mcat Biological Sciences

Cryptosporidium is a genus of gastrointestinal parasite that infects the intestinal epithelium of mammals. Cryptosporidium is water-borne, and is an apicomplexan parasite. This phylum also includes Plasmodium, Babesia, and Toxoplasma. 

Apicomplexans are unique due to their apicoplast, an apical organelle that helps penetrate mammalian epithelium. In the case of cryptosporidium, there is an interaction between the surface proteins of mammalian epithelial tissue and those of the apical portion of the cryptosporidium infective stage, or oocyst. A scientist is conducting an experiment to test the hypothesis that the oocyst secretes a peptide compound that neutralizes intestinal defense cells. These defense cells are resident in the intestinal epithelium, and defend the tissue by phagocytizing the oocysts. 

She sets up the following experiment:

As the neutralizing compound was believed to be secreted by the oocyst, the scientist collected oocysts onto growth media. The oocysts were grown among intestinal epithelial cells, and then the media was collected. The media was then added to another plate where Toxoplasma gondii was growing with intestinal epithelial cells. A second plate of Toxoplasma gondii was grown with the same type of intestinal epithelium, but no oocyst-sourced media was added.

You are conducting a study of an isolated tribe in New Guinea, and you find that there is widespread resistance to cryptosporidium infection. Upon examination, you find that the resistance is caused by a change in one nucleotide pair in a gene on chromosome 13. What kind of genetic change does this likely reflect?

Possible Answers:

Chromosomal change

Fragile X

Single nucleotide polymorphism (SNP)

Genomic imprinting

Copy number variant

Correct answer:

Single nucleotide polymorphism (SNP)

Explanation:

This would be an example of a single nucleotide polymorphism. A fairly common variant is some change at a single base pair in human DNA. It is possible that this base pair change results in a modified protein that functions just as well as the normal protein in most conditions.

Some of these changes may, simply by chance, be better at resisting disease. When exposed to stress, such as a disease epidemic, it is possible this variant of normal becomes the most widespread genotype. This is especially noticeable in an isolated population, like a tribe in New Guinea. Note that not all single nucleotide polymorphisms will have positive effects, and in some cases can cause disease instead of resistance.

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