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PSAT Math : Algebra

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Example Questions

Example Question #51 : Exponents

Simplify:

$\left ( \frac{x}{2t^{2}} \right )^{3}$

Possible Answers:

$\frac{x^{3}}{ 9t^{6} }$

$\frac{x^{3}}{ 8 t^{6} }$

$\frac{ 6 t^{6} }{x^{3}}$

$\frac{x^{3}}{ 6 t^{6} }$

$\frac{ 8 t^{6} }{x^{3}}$

Correct answer:

$\frac{x^{3}}{ 8 t^{6} }$

Explanation:

Apply the the various properties of exponents:

$\left ( \frac{x}{2t^{2}} \right )^{3}$

$=\frac{x^{3}}{ \left ( 2t^{2} \right ) ^{3}}$

$=\frac{x^{3}}{ 2^{3} \left ( t^{2} \right )^{3} }$

$=\frac{x^{3}}{ 8 t^{2 \cdot 3} }$

$=\frac{x^{3}}{ 8 t^{6} }$

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Example Question #1155 : Psat Mathematics

$\textup{If }4^{3}\times8^{2}=2^{y}\textup{, what is the value of }y\textup{ ?}$

Possible Answers:

Correct answer:

Explanation:

$\textup{4 and 8 are powers of 2. Find the common base and set exponents equal:}$

$\left ( 2^{2}\right )^{3}\times \left ( 2^{3}\right )^{2}=2^{y}\: \; \; \; \; \; \;2^{6}\times 2^{6}=2^{y}$

$2^{12}=2^{y}\: \: \: \: \: \: \:12=y$

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Example Question #501 : Algebra

Simplify: $x^{5}\cdot x^{2}$

Possible Answers:

$x^{7}$

$2x^{7}$

This expression cannot be simplified any further

$2x^{10}$

$x^{10}$

Correct answer:

$x^{7}$

Explanation:

When you are multiplying and the bases are the same, you add the exponents together. Because both bases are you add 5+2=7 as your new exponent. You then keep the same base, , to the 7th power.

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Example Question #61 : Exponents

Solve for :

$\sqrt[3]{x-3} = 2$

Possible Answers:

$None\ of\ the\ above$

Correct answer:

Explanation:

$\left ( \sqrt[3]{x-3} \right )^{3} = 2^{3}$

Now the left side equals x-3 and the right side equals 8. Hence:

x-3 = 8

Therefore must be equal to 11.

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Example Question #1 : Squaring / Square Roots / Radicals

Simplify the radical.

$\sqrt{3283}$

Possible Answers:

$56$

$7\sqrt{67}$

$7\sqrt{63}$

$67\sqrt{49}$

$57.3$

Correct answer:

$7\sqrt{67}$

Explanation:

We can break the square root down into 2 roots of 67 and 49. 49 is a perfect square and reduces to 7.

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Example Question #502 : Algebra

Expand:

$\left ( 10x+ \frac{1}{5}\right )^{2}$

Possible Answers:

$100x^{2} + \frac{1}{10}$

$100x^{2} + 2x + \frac{1}{10}$

$100x^{2} + 4x + \frac{1}{25}$

$100x^{2} + \frac{1}{25}$

$100x^{2} + 2x + \frac{1}{25}$

Correct answer:

$100x^{2} + 4x + \frac{1}{25}$

Explanation:

Use the perfect square trinomial pattern, setting $A = 10x , B = \frac{1}{5}$ :

$(A + B)^{2} = A^{2} + 2AB + B ^{2}$

$\left ( 10x + \frac{1}{5} \right )^{2} = (10x)^{2} + 2 (10x) \left ( \frac{1}{5} \right ) + \left ( \frac{1}{5} \right ) ^{2}$

$= 100x^{2} + 4x + \frac{1}{25}$

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Example Question #2 : Squaring / Square Roots / Radicals

If $\left (5 x^{2 } - x + 1\right )^{2}$ is expanded, what is the coefficient of $x^{2}$ ?

Possible Answers:

There is no $x^{2}$ term in the expansion of $\left (5 x^{2 } - x + 1\right )^{2}$ .

Correct answer:

Explanation:

$\left (5 x^{2 } - x + 1\right )^{2}$

$= \left (5 x^{2 } - x + 1\right ) \left (5 x^{2 } - x + 1\right )$

$= 5 x^{2 } \left (5 x^{2 } - x + 1\right ) - x \left (5 x^{2 } - x + 1\right ) + 1 \left (5 x^{2 } - x + 1\right )$

$= 5 x^{2 } \cdot 5 x^{2 } - 5 x^{2 } \cdot x + 5x^{2 } \cdot 1 - x \cdot 5 x^{2 }+ x \cdot x - x \cdot 1+ 1\cdot 5 x^{2 } - 1 \cdot x + 1\cdot 1$

$= 25 x^{4 } - 5 x^{3 } + 5x^{2 } - 5 x^{3 }+ x ^{2 } - x + 5 x^{2 } - x + 1$

$= 25 x^{4 } - 5 x^{3 } - 5 x^{3 } + 5x^{2 }+ 5 x^{2 } + x ^{2 } - x - x + 1$

$= 25 x^{4 } -10 x^{3 } + 11 x^{2 } -2 x + 1$

The coefficient of $x^{2}$ is therefore 11.

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Example Question #3 : Squaring / Square Roots / Radicals

If $\left (5 x^{2 } - x + 1\right )^{2}$ is expanded, what is the coefficient of $x^{3}$ ?

Possible Answers:

There is no $x^{3}$ term in the expansion of $\left (5 x^{2 } - x + 1\right )^{2}$ .

Correct answer:

Explanation:

$\left (5 x^{2 } - x + 1\right )^{2}$

$= \left (5 x^{2 } - x + 1\right ) \left (5 x^{2 } - x + 1\right )$

$= 5 x^{2 } \left (5 x^{2 } - x + 1\right ) - x \left (5 x^{2 } - x + 1\right ) + 1 \left (5 x^{2 } - x + 1\right )$

$= 5 x^{2 } \cdot 5 x^{2 } - 5 x^{2 } \cdot x + 5x^{2 } \cdot 1 - x \cdot 5 x^{2 }+ x \cdot x - x \cdot 1+ 1\cdot 5 x^{2 } - 1 \cdot x + 1\cdot 1$

$= 25 x^{4 } - 5 x^{3 } + 5x^{2 } - 5 x^{3 }+ x ^{2 } - x + 5 x^{2 } - x + 1$

$= 25 x^{4 } - 5 x^{3 } - 5 x^{3 } + 5x^{2 }+ 5 x^{2 } + x ^{2 } - x - x + 1$

$= 25 x^{4 } -10 x^{3 } + 11 x^{2 } -2 x + 1$

The coefficient of $x^{3}$ is therefore 10.

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Example Question #3 : Squaring / Square Roots / Radicals

Expand:

$\left ( 10x+ 0.8\right )^{2}$

Possible Answers:

$100x^{2} + 1.6x + 6.4$

$100x^{2}+8x + 0.64$

$100x^{2} + 16x + 0.64$

$100x^{2} +0. 16x + 0.064$

$100x^{2} +0.8x+ 6.4$

Correct answer:

$100x^{2} + 16x + 0.64$

Explanation:

Use the perfect square trinomial pattern, setting A = 10x , B = 0.8 :

$(A + B)^{2} = A^{2} + 2AB + B ^{2}$

$(10x + 0.8)^{2} = \left (10x \right )^{2} + 2 \cdot 10x \cdot 0.8 + 0.8^{2}$

$(10x + 0.8)^{2} = 100x^{2} + 16x + 0.64$

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Example Question #1 : How To Factor A Common Factor Out Of Squares

x² = 36

Quantity A: x

Quantity B: 6

Possible Answers:

Quantity A is greater

Quantity B is greater

The relationship cannot be determined from the information given

The two quantities are equal

Correct answer:

The relationship cannot be determined from the information given

Explanation:

x² = 36 -> it is important to remember that this leads to two answers.

x = 6 or x = -6.

If x = 6: A = B.

If x = -6: A < B.

Thus the relationship cannot be determined from the information given.

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PSAT Math : Algebra

Study concepts, example questions & explanations for PSAT Math

All PSAT Math Resources

Example Questions

Example Question #51 : Exponents

Example Question #1155 : Psat Mathematics

Example Question #501 : Algebra

Example Question #61 : Exponents

Example Question #1 : Squaring / Square Roots / Radicals

Example Question #502 : Algebra

Example Question #2 : Squaring / Square Roots / Radicals

Example Question #3 : Squaring / Square Roots / Radicals

Example Question #3 : Squaring / Square Roots / Radicals

Example Question #1 : How To Factor A Common Factor Out Of Squares

All PSAT Math Resources

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