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SAT Math : SAT Mathematics

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Example Questions

Example Question #2 : Squaring / Square Roots / Radicals

Simplify the expression.

$\sqrt{5}(2\sqrt{3}+\sqrt{12})$

Possible Answers:

$10\sqrt{15}$

$4\sqrt{15}$

$3\sqrt{2}$

$10\sqrt{3}$

$4\sqrt{30}$

Correct answer:

$4\sqrt{15}$

Explanation:

Use the distributive property for radicals.

$\sqrt{5}(2\sqrt{3}+\sqrt{12})$

Multiply all terms by $\sqrt{5}$ .

$(\sqrt{5}*2\sqrt{3})+(\sqrt{5}*\sqrt{12})$

Combine terms under radicals.

$2\sqrt{3*5}+\sqrt{12*5}$

$2\sqrt{15}+\sqrt{60}$

Look for perfect square factors under each radical. has a perfect square of . The can be factored out.

$2\sqrt{15}+\sqrt{4*15}$

$2\sqrt{15}+2\sqrt{15}$

Since both radicals are the same, we can add them.

$4\sqrt{15}$

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Example Question #4 : Squaring / Square Roots / Radicals

Which of the following expression is equal to

$\sqrt{(45)(9)+(27)(36)}$

Possible Answers:

$9\sqrt{17}$

$9\sqrt{19}$

$9\sqrt{15}$

$7\sqrt{17}$

$7\sqrt{15}$

Correct answer:

$9\sqrt{17}$

Explanation:

$\sqrt{(45)(9)+(27)(36)}$

When simplifying a square root, consider the factors of each of its component parts:

$\sqrt{(3^2)\times5\times(3^{2})+(3^{3})(2^2)(3^2)}$

Combine like terms:

$\sqrt{5(3^4)+(2^2)(3^5)}$

Remove the common factor, 3^4 :

$\sqrt{(3^4)\times(5+3\times(2^2))}$

Pull the $\sqrt{3^4}$ outside of the equation as 3^2 :

$(3^2)\sqrt{5+12}=9\sqrt{17}$

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Example Question #581 : Algebra

Which of the following is equal to the following expression?

$\sqrt{(16)(8)+(32)(20)}$

Possible Answers:

$2^{3}\sqrt{6}$

$2^{4}\sqrt{5}$

$2^4\sqrt{3}$

$2^{3}\sqrt{10}$

$2^{7}\sqrt{5}$

Correct answer:

$2^4\sqrt{3}$

Explanation:

$\sqrt{(16)(8)+(32)(20)}$

First, break down the components of the square root:

$\sqrt{(2^{4})(2^{3})+(2^{5})(2^{2})\times 5}$

Combine like terms. Remember, when multiplying exponents, add them together:

$\sqrt{(2^{7})+(2^{7})\times5}$

Factor out the common factor of 2^7 :

$\sqrt{(2^{7})(1+5)}$

$\sqrt{(2^7)\times6}$

Factor the :

$\sqrt{(2^7)\times2\times3}$

Combine the factored with the 2^7 :

$\sqrt{(2^{8})\times3}$

Now, you can pull $\sqrt{2^8}$ out from underneath the square root sign as 2^4 :

$2^4\sqrt{3}$

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Example Question #5 : Squaring / Square Roots / Radicals

Which of the following expressions is equal to the following expression?

$\sqrt{(27)(45)(125)}$

Possible Answers:

$225\sqrt{3}$

$135\sqrt{5}$

$205\sqrt{3}$

$75\sqrt{20}$

$125\sqrt{27}$

Correct answer:

$225\sqrt{3}$

Explanation:

$\sqrt{(27)(45)(125)}$

First, break down the component parts of the square root:

$\sqrt{(3^{3})(5\times 3^{2})(5^{3})}$

Combine like terms in a way that will let you pull some of them out from underneath the square root symbol:

$\sqrt{(5^{4})(3^4)(3)}$

Pull out the terms with even exponents and simplify:

$(5^{2})(3^{2})\sqrt{3}=225\sqrt{3}$

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Example Question #1 : Complex Numbers

From $\frac{3}{2} + \frac{1}{4} i$ , subtract its complex conjugate. What is the difference ?

Possible Answers:

$\frac{7}{4} + \frac{7}{4} i$

$-\frac{1}{2} i$

$\frac{1}{2} i$

Correct answer:

$\frac{1}{2} i$

Explanation:

The complex conjugate of a complex number a+bi is a - bi , so $\frac{3}{2} + \frac{1}{4} i$ has $\frac{3}{2} - \frac{1}{4} i$ as its complex conjugate. Subtract the latter from the former:

$\left (\frac{3}{2} + \frac{1}{4} i \right ) - \left ( \frac{3}{2} - \frac{1}{4} i \right )$

$= \frac{3}{2} + \frac{1}{4} i - \frac{3}{2}+ \frac{1}{4} i$

$= \frac{3}{2}- \frac{3}{2} + \frac{1}{4} i + \frac{1}{4} i$

$= \frac{1}{2} i$

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Example Question #2 : Complex Numbers

From $17 - i \sqrt{17}$ , subtract its complex conjugate.

Possible Answers:

$2 i \sqrt{17}$

$- 2 i \sqrt{17}$

Correct answer:

$- 2 i \sqrt{17}$

Explanation:

The complex conjugate of a complex number a - bi is a+ bi . Therefore, the complex conjugate of $17 - i \sqrt{17}$ is $17 + i \sqrt{17}$ ; subtract the latter from the former by subtracting real parts and subtracting imaginary parts, as follows:

$(17 - i \sqrt{17})- (17 + i \sqrt{17})$

$= 17 - i \sqrt{17} - 17 - i \sqrt{17}$

$= 17 - 17 - i \sqrt{17} - i \sqrt{17}$

$= - 2 i \sqrt{17}$

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Example Question #3 : Complex Numbers

From $7 + i \sqrt {7 }$ , subtract its complex conjugate.

Possible Answers:

$2i \sqrt {7 }$

$-2i \sqrt {7 }$

Correct answer:

$2i \sqrt {7 }$

Explanation:

The complex conjugate of a complex number a+ bi is a - bi . Therefore, the complex conjugate of $7 + i \sqrt {7 }$ is $7 - i \sqrt {7 }$ ; subtract the latter from the former by subtracting real parts and subtracting imaginary parts, as follows:

$(7 + i \sqrt {7 })- (7 - i \sqrt {7 })$

$= 7- 7 + i \sqrt {7 }- (- i \sqrt {7 })$

$= i \sqrt {7 }+ i \sqrt {7 }$

$=2i \sqrt {7 }$

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Example Question #11 : Squaring / Square Roots / Radicals

Simplify: $\sqrt{-3}+\sqrt{-9}+\sqrt{-16}$

Possible Answers:

$2i\sqrt7$

$i\sqrt3 +7i$

$i\sqrt3-i$

$i\sqrt3 +i$

$i\sqrt3 -7i$

Correct answer:

$i\sqrt3 +7i$

Explanation:

Rewrite $\sqrt{-3}+\sqrt{-9}+\sqrt{-16}$ in their imaginary terms.

$i=\sqrt{-1}$

$\sqrt{-3}+\sqrt{-9}+\sqrt{-16}=i\sqrt3+3i+4i = i\sqrt3 +7i$

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Example Question #3 : New Sat Math No Calculator

Add $5 + i \sqrt {5 }$ and its complex conjugate.

Possible Answers:

$-2 i \sqrt{5}$

$2 i \sqrt{5}$

Correct answer:

Explanation:

The complex conjugate of a complex number a+ bi is a - bi . Therefore, the complex conjugate of $5 + i \sqrt {5 }$ is $5 - i \sqrt {5 }$ ; add them by adding real parts and adding imaginary parts, as follows:

$(5 + i \sqrt {5 } )+( 5 - i \sqrt {5 })$

$= 5 + 5 + i \sqrt {5 } - i \sqrt {5 }$

= 10 ,

the correct response.

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Example Question #3 : Complex Numbers

Add $13 - i \sqrt{13}$ to its complex conjugate.

Possible Answers:

$2i \sqrt{13}$

$-2i \sqrt{13}$

Correct answer:

Explanation:

The complex conjugate of a complex number a - bi is a+ bi . Therefore, the complex conjugate of $13 - i \sqrt{13}$ is $13 + i \sqrt{13}$ ; add them by adding real parts and adding imaginary parts, as follows:

$(13 - i \sqrt{13} )+( 13 + i \sqrt{13})$

$= 13+13 - i \sqrt {13 }+ i \sqrt {13}$

= 26

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SAT Math : SAT Mathematics

Study concepts, example questions & explanations for SAT Math

All SAT Math Resources

Example Questions

Example Question #2 : Squaring / Square Roots / Radicals

Example Question #4 : Squaring / Square Roots / Radicals

Example Question #581 : Algebra

Example Question #5 : Squaring / Square Roots / Radicals

Example Question #1 : Complex Numbers

Example Question #2 : Complex Numbers

Example Question #3 : Complex Numbers

Example Question #11 : Squaring / Square Roots / Radicals

Example Question #3 : New Sat Math No Calculator

Example Question #3 : Complex Numbers

All SAT Math Resources

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