SSAT Elementary Level Math : How to find the area of a rectangle

Study concepts, example questions & explanations for SSAT Elementary Level Math

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Example Questions

Example Question #171 : Quadrilaterals

What is the length of a rectangular room with an area of \(\displaystyle 50ft^2\) and a width of \(\displaystyle 5ft?\)

 

Possible Answers:

\(\displaystyle 9ft\)

\(\displaystyle 11ft\)

\(\displaystyle 8ft\)

\(\displaystyle 12ft\)

\(\displaystyle 10ft\)

Correct answer:

\(\displaystyle 10ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 50=l\times 5\)

\(\displaystyle \frac{50}{5}=\frac{l\times 5}{5}\)

\(\displaystyle 10=l\)

Example Question #223 : Quadrilaterals

What is the length of a rectangular room with an area of \(\displaystyle 80ft^2\) and a width of \(\displaystyle 10ft?\)

 

Possible Answers:

\(\displaystyle 10ft\)

\(\displaystyle 9ft\)

\(\displaystyle 8ft\)

\(\displaystyle 7ft\)

\(\displaystyle 11ft\)

Correct answer:

\(\displaystyle 8ft\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 80=l\times 10\)

\(\displaystyle \frac{80}{10}=\frac{l\times 10}{10}\)

\(\displaystyle 8=l\)

Example Question #71 : How To Find The Area Of A Rectangle

What is the length of a rectangular yard with an area of \(\displaystyle 8m^2\) and a width of \(\displaystyle 4m?\)

 

Possible Answers:

\(\displaystyle 2m\)

\(\displaystyle 6m\)

\(\displaystyle 3m\)

\(\displaystyle 4m\)

\(\displaystyle 5m\)

Correct answer:

\(\displaystyle 2m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 8=l\times 4\)

\(\displaystyle \frac{8}{4}=\frac{l\times 4}{4}\)

\(\displaystyle 2=l\)

Example Question #132 : Solve Problems Involving Measurement And Conversion Of Measurements

What is the length of a rectangular yard with an area of \(\displaystyle 12m^2\) and a width of \(\displaystyle 4m?\)

 

Possible Answers:

\(\displaystyle 5m\)

\(\displaystyle 6m\)

\(\displaystyle 3m\)

\(\displaystyle 4m\)

\(\displaystyle 2m\)

Correct answer:

\(\displaystyle 3m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 12=l\times 4\)

\(\displaystyle \frac{12}{4}=\frac{l\times 4}{4}\)

\(\displaystyle 3=l\)

Example Question #41 : Solving For Length

What is the length of a rectangular yard with an area of \(\displaystyle 15m^2\) and a width of \(\displaystyle 3m?\)

 

Possible Answers:

\(\displaystyle 3m\)

\(\displaystyle 4m\)

\(\displaystyle 6m\)

\(\displaystyle 5m\)

\(\displaystyle 5m\)

Correct answer:

\(\displaystyle 5m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 15=l\times 3\)

\(\displaystyle \frac{15}{3}=\frac{l\times 3}{3}\)

\(\displaystyle 5=l\)

Example Question #351 : Geometry

What is the length of a rectangular yard with an area of \(\displaystyle 16m^2\) and a width of \(\displaystyle 2m?\)

 

Possible Answers:

\(\displaystyle 9m\)

\(\displaystyle 7m\)

\(\displaystyle 8m\)

\(\displaystyle 5m\)

\(\displaystyle 6m\)

Correct answer:

\(\displaystyle 8m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 16=l\times 2\)

\(\displaystyle \frac{16}{2}=\frac{l\times 2}{2}\)

\(\displaystyle 8=l\)

Example Question #52 : Solving For Length

What is the length of a rectangular yard with an area of \(\displaystyle 20m^2\) and a width of \(\displaystyle 5m?\)

 

Possible Answers:

\(\displaystyle 3m\)

\(\displaystyle 1m\)

\(\displaystyle 5m\)

\(\displaystyle 4m\)

\(\displaystyle 2m\)

Correct answer:

\(\displaystyle 4m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 20=l\times 5\)

\(\displaystyle \frac{20}{5}=\frac{l\times 5}{5}\)

\(\displaystyle 4=l\)

Example Question #53 : Solving For Length

What is the length of a rectangular yard with an area of \(\displaystyle 24m^2\) and a width of \(\displaystyle 4m?\)

 

Possible Answers:

\(\displaystyle 9m\)

\(\displaystyle 6m\)

\(\displaystyle 7m\)

\(\displaystyle 10m\)

\(\displaystyle 8m\)

Correct answer:

\(\displaystyle 6m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 24=l\times 4\)

\(\displaystyle \frac{24}{4}=\frac{l\times 4}{4}\)

\(\displaystyle 6=l\)

Example Question #1361 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of \(\displaystyle 25m^2\) and a width of \(\displaystyle 5m?\)

 

Possible Answers:

\(\displaystyle 8m\)

\(\displaystyle 4m\)

\(\displaystyle 5m\)

\(\displaystyle 7m\)

\(\displaystyle 6m\)

Correct answer:

\(\displaystyle 5m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 25=l\times 5\)

\(\displaystyle \frac{25}{5}=\frac{l\times 5}{5}\)

\(\displaystyle 5=l\)

Example Question #1362 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of \(\displaystyle 27m^2\) and a width of \(\displaystyle 3m?\)

 

Possible Answers:

\(\displaystyle 8m\)

\(\displaystyle 9m\)

\(\displaystyle 11m\)

\(\displaystyle 7m\)

\(\displaystyle 10m\)

Correct answer:

\(\displaystyle 9m\)

Explanation:

\(\displaystyle A=l\times w\)

We have the area and the width, so we can plug those values into our equation and solve for our unknown. 

\(\displaystyle 27=l\times 3\)

\(\displaystyle \frac{27}{3}=\frac{l\times 3}{3}\)

\(\displaystyle 9=l\)

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