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SSAT Elementary Level Math : How to find the area of a rectangle

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #172 : Measurement & Data

What is the length of a rectangular yard with an area of 28m^2 $\displaystyle 28m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 8m$

$\displaystyle 4m$

$\displaystyle 6m$

$\displaystyle 5m$

$\displaystyle 7m$

Correct answer:

$\displaystyle 7m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$28=l\times 4$ $\displaystyle 28=l\times 4$

$\frac{28}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{28}{4}=\frac{l\times 4}{4}$

7=l $\displaystyle 7=l$

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Example Question #352 : Geometry

What is the length of a rectangular yard with an area of 30m^2 $\displaystyle 30m^2$ and a width of 5m? $\displaystyle 5m?$

Possible Answers:

$\displaystyle 3m$

$\displaystyle 5m$

$\displaystyle 4m$

$\displaystyle 2m$

$\displaystyle 6m$

Correct answer:

$\displaystyle 6m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$30=l\times 5$ $\displaystyle 30=l\times 5$

$\frac{30}{5}=\frac{l\times 5}{5}$ $\displaystyle \frac{30}{5}=\frac{l\times 5}{5}$

6=l $\displaystyle 6=l$

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Example Question #1361 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of 32m^2 $\displaystyle 32m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 8m$

12m $\displaystyle 12m$

10m $\displaystyle 10m$

13m $\displaystyle 13m$

$\displaystyle 9m$

Correct answer:

$\displaystyle 8m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$32=l\times 4$ $\displaystyle 32=l\times 4$

$\frac{32}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{32}{4}=\frac{l\times 4}{4}$

8=l $\displaystyle 8=l$

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Example Question #1362 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of 33m^2 $\displaystyle 33m^2$ and a width of 3m? $\displaystyle 3m?$

Possible Answers:

11m $\displaystyle 11m$

10m $\displaystyle 10m$

12m $\displaystyle 12m$

$\displaystyle 8m$

$\displaystyle 9m$

Correct answer:

11m $\displaystyle 11m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$33=l\times 3$ $\displaystyle 33=l\times 3$

$\frac{33}{3}=\frac{l\times 3}{3}$ $\displaystyle \frac{33}{3}=\frac{l\times 3}{3}$

11=l $\displaystyle 11=l$

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Example Question #1363 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of 35m^2 $\displaystyle 35m^2$ and a width of 5m? $\displaystyle 5m?$

Possible Answers:

$\displaystyle 8m$

11m $\displaystyle 11m$

$\displaystyle 9m$

10m $\displaystyle 10m$

$\displaystyle 7m$

Correct answer:

$\displaystyle 7m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$35=l\times 5$ $\displaystyle 35=l\times 5$

$\frac{35}{5}=\frac{l\times 5}{5}$ $\displaystyle \frac{35}{5}=\frac{l\times 5}{5}$

7=l $\displaystyle 7=l$

Report an Error

Example Question #1364 : Common Core Math: Grade 4

What is the length of a rectangular yard with an area of 36m^2 $\displaystyle 36m^2$ and a width of 4m? $\displaystyle 4m?$

Possible Answers:

$\displaystyle 8m$

11m $\displaystyle 11m$

$\displaystyle 9m$

12m $\displaystyle 12m$

10m $\displaystyle 10m$

Correct answer:

$\displaystyle 9m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$36=l\times 4$ $\displaystyle 36=l\times 4$

$\frac{36}{4}=\frac{l\times 4}{4}$ $\displaystyle \frac{36}{4}=\frac{l\times 4}{4}$

9=l $\displaystyle 9=l$

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Example Question #61 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 36m^2 $\displaystyle 36m^2$ and a width of 3m? $\displaystyle 3m?$

Possible Answers:

11m $\displaystyle 11m$

12m $\displaystyle 12m$

10m $\displaystyle 10m$

14m $\displaystyle 14m$

13m $\displaystyle 13m$

Correct answer:

12m $\displaystyle 12m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$36=l\times 3$ $\displaystyle 36=l\times 3$

$\frac{36}{3}=\frac{l\times 3}{3}$ $\displaystyle \frac{36}{3}=\frac{l\times 3}{3}$

12=l $\displaystyle 12=l$

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Example Question #62 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 14m^2 $\displaystyle 14m^2$ and a width of 2m? $\displaystyle 2m?$

Possible Answers:

$\displaystyle 8m$

$\displaystyle 7m$

$\displaystyle 6m$

$\displaystyle 5m$

$\displaystyle 4m$

Correct answer:

$\displaystyle 7m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$14=l\times 2$ $\displaystyle 14=l\times 2$

$\frac{14}{2}=\frac{l\times 2}{2}$ $\displaystyle \frac{14}{2}=\frac{l\times 2}{2}$

7=l $\displaystyle 7=l$

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Example Question #601 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

What is the length of a rectangular yard with an area of 16m^2 $\displaystyle 16m^2$ and a width of 8m? $\displaystyle 8m?$

Possible Answers:

$\displaystyle 5m$

$\displaystyle 4m$

$\displaystyle 6m$

$\displaystyle 2m$

$\displaystyle 3m$

Correct answer:

$\displaystyle 2m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$16=l\times 8$ $\displaystyle 16=l\times 8$

$\frac{16}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{16}{8}=\frac{l\times 8}{8}$

2=l $\displaystyle 2=l$

Report an Error

Example Question #63 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular yard with an area of 24m^2 $\displaystyle 24m^2$ and a width of 3m? $\displaystyle 3m?$

Possible Answers:

$\displaystyle 4m$

$\displaystyle 6m$

$\displaystyle 7m$

$\displaystyle 8m$

$\displaystyle 5m$

Correct answer:

$\displaystyle 8m$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$24=l\times 3$ $\displaystyle 24=l\times 3$

$\frac{24}{3}=\frac{l\times 3}{3}$ $\displaystyle \frac{24}{3}=\frac{l\times 3}{3}$

8=l $\displaystyle 8=l$

Report an Error

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : How to find the area of a rectangle

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #172 : Measurement & Data

Example Question #352 : Geometry

Example Question #1361 : Common Core Math: Grade 4

Example Question #1362 : Common Core Math: Grade 4

Example Question #1363 : Common Core Math: Grade 4

Example Question #1364 : Common Core Math: Grade 4

Example Question #61 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #62 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #601 : Isee Middle Level (Grades 7 8) Quantitative Reasoning

Example Question #63 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

All SSAT Elementary Level Math Resources

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