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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #292 : How To Multiply

Find the product of and .

Possible Answers:

Correct answer:

Explanation:

To find the product you must multiply.

$3\times7=21$

Another method is to make groups of and add them up.

ooooooo ooooooo ooooooo = 21

7+7+7=21

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Example Question #293 : How To Multiply

Margaret needs to rent chairs for a party on Saturday. If each table seats people and she has tables, how many chairs does she need to rent?

Possible Answers:

Correct answer:

Explanation:

Each person needs chair. Since each table seats people and there are tables, you must multiply.

$8 \times 5 = 40$

Another method is to make groups of and add them up.

ooooo+ooooo+ooooo+ooooo+ooooo+ooooo+ooooo+ooooo = 40

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Example Question #294 : How To Multiply

Find the product.

Brittney bought candy bars. Each candy bar costs $\$0.89$ . How much did she spend on all four candy bars?

Possible Answers:

$\$3.45$

$\$3.46$

$\$3.56$

$\$3.65$

Correct answer:

$\$3.56$

Explanation:

To solve, you must find the product (or multiply) and $\$0.89$ .

$4 \times 0.89=3.56$

You can also add to solve:

0.89+0.89+0.89+0.89=3.56

Brittney spent $\$3.56$ on the four candy bars.

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Example Question #2971 : Numbers And Operations

If one apples weighs ounces, how much do three apples weigh?

Possible Answers:

$14\ ounces$

$22\ ounces$

$45\ ounces$

$33\ ounces$

30ounces

Correct answer:

$33\ ounces$

Explanation:

Multiply the number of apples by the weight.

$3\times 11 = 33$

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Example Question #2972 : Numbers And Operations

$\frac{\begin{array}[b]{r}4\\ \times 2\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

Multiplication can be thought of as repeated addition, or as objects in a group.

$4\times2$ means adding four times.

2+2+2+2=8 and $4\times2=8$

Or we can think of this as grouping objects. We have groups, with objects in each group. We can count up the total number of objects, in this case triangles.

Screen shot 2015 08 17 at 9.04.25 pm

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Example Question #2973 : Numbers And Operations

The lizards in a cage at the pet store have an average of spots on their bodies. If there are lizards in the cage, how many spots are on all of the lizards in total.

Possible Answers:

256

512

576

Correct answer:

512

Explanation:

The average is the ratio of the total number of spots to the total number of lizards.

Therefore

$8 = \frac{x}{64}$

Multiply both sides by 64 to obtain:

x = 512

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Example Question #1 : Measurement & Data

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 9.25.27 am

Possible Answers:

400

40,000

4,000

400,000

4000,000

Correct answer:

400,000

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1km}{100,000 cm}=\frac{4km}{x}$

First we cross multiply.

1km(x)=4km(100,000cm)

Then we divide each side by 1km to isolate the .

$\frac{1km(x)}{1km}=\frac{4km(100,000cm)}{1km}$

x=400,000 cm

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Example Question #1 : Solve Problems Involving Measurement And Conversion Of Measurements

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 9.29.13 am

Possible Answers:

400

4000

40,000

Correct answer:

400

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1m}{100 cm}=\frac{4m}{x}$

First we cross multiply.

1m(x)=4m(100cm)

Then we divide each side by to isolate the .

$\frac{1m(x)}{1m}=\frac{4m(100cm)}{1m}$

x=400 cm

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Example Question #2 : Measurement & Data

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 9.30.02 am

Possible Answers:

20,000

2000

200

Correct answer:

200

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1m}{100 cm}=\frac{2m}{x}$

First we cross multiply.

1m(x)=2m(100cm)

Then we divide each side by to isolate the .

$\frac{1m(x)}{1m}=\frac{2m(100cm)}{1m}$

x=200 cm

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Example Question #3 : Measurement & Data

Fill in the missing piece of the table.

Screen shot 2015 09 01 at 9.31.34 am

Possible Answers:

5000

500

50,000

Correct answer:

500

Explanation:

To solve this problem we can set up a proportion and cross multiply to solve for our unknown.

$\frac{1m}{100 cm}=\frac{5m}{x}$

First we cross multiply.

1m(x)=5m(100cm)

Then we divide each side by to isolate the .

$\frac{1m(x)}{1m}=\frac{5m(100cm)}{1m}$

x=500 cm

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #292 : How To Multiply

Example Question #293 : How To Multiply

Example Question #294 : How To Multiply

Example Question #2971 : Numbers And Operations

Example Question #2972 : Numbers And Operations

Example Question #2973 : Numbers And Operations

Example Question #1 : Measurement & Data

Example Question #1 : Solve Problems Involving Measurement And Conversion Of Measurements

Example Question #2 : Measurement & Data

Example Question #3 : Measurement & Data

All SSAT Elementary Level Math Resources

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