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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #31 : Solve Multistep Word Problems Using The Four Operations: Ccss.Math.Content.4.Oa.A.3

students are going on a field trip. students can ride in each car. How many cars will they need for the field trip?

Possible Answers:

Correct answer:

Explanation:

When we have a set of something that we are splitting up into groups, we divide. In this case, we are dividing students up into cars. We will let represent the number of cars they will need.

$33\div4=c$

$\frac{\begin{array}[b]{r} \ 8\\ 4{\overline{\smash{)}33}}\\ -\ 32\end{array}}{ \ \ \ \ \ 1}$

Our answer is with a remainder of . This means that they will have full cars of people, but there is person left over. So they need cars in order for every student to be in a car.

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Example Question #3552 : Operations

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 71\\ 5{\overline{\smash{)}355}}\\ -\ 35 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 35$

$5\times 53$

$5\times 51$

$5\times 71$

$5\times 101$

Correct answer:

$5\times 71$

Explanation:

The computation shows that $355\div5=71$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 71}\\ {\color{Green} 5}{\overline{\smash{)}355}}\\ -\ 35 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times71=355+0$

Simplify.

$5\times71=355$

The correct answer is $5\times 71$

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Example Question #11 : Multiplying And Dividing Within 100

$6{\overline{\smash{)}36}}$

Possible Answers:

Correct answer:

Explanation:

$6{\overline{\smash{)}36}}$

To solve this division problem, we can think of it as a missing factor problem.

Think: What times equals 36?

$6\times6=36$

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Example Question #12 : Multiplying And Dividing Within 100

$6{\overline{\smash{)}54}}$

Possible Answers:

Correct answer:

Explanation:

$6{\overline{\smash{)}54}}$

To solve this division problem, we can think of it as a missing factor problem.

Think: What times equals 54?

$6\times9=54$

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Example Question #41 : The Number System

Use the computation shown to find the products:

$\frac{\begin{array}[b]{r} \ 81\\ 5{\overline{\smash{)}405}}\\ -\ 40 \ \smash \ \end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

Possible Answers:

$5\times 81$

$5\times 40$

$5\times 101$

$5\times 91$

$5\times 85$

Correct answer:

$5\times 81$

Explanation:

The computation shows that $405\div5=81$ with a remainder of .

$\frac{\begin{array}[b]{r} \ {\color{Green} 81}\\ {\color{Green} 5}{\overline{\smash{)}405}}\\ -\ 40 \smash{\downarrow}\end{array}}{ \ \ \ \space \frac{\begin{array}[b]{r}00{ 5\ \ }\\ -\ \ \ 5\ \ \end{array}}{ \ \ \ \space} }$

So it must be that:

$5\times81=405+0$

Simplify.

$5\times81=405$

The correct answer is $5\times 81$

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Example Question #501 : How To Divide

$2{\overline{\smash{)}20}}$

Possible Answers:

Correct answer:

Explanation:

$2{\overline{\smash{)}20}}$

To solve this division problem, we can think of it as a missing factor problem.

Think: What times equals 20?

$2\times10=20$

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Example Question #502 : How To Divide

$3{\overline{\smash{)}18}}$

Possible Answers:

Correct answer:

Explanation:

$3{\overline{\smash{)}18}}$

To solve this division problem, we can think of it as a missing factor problem.

Think: What times equals 18?

$3\times6=18$

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Example Question #503 : How To Divide

I have oranges and boxes. I am going to put the same number of oranges in each box. How many oranges will be in each box?

Possible Answers:

Correct answer:

Explanation:

Looking at the picture below, we have a total of oranges and boxes. Each box has oranges in it.

Because we are splitting the oranges up into equal groups, this is a division problem.

Let's let equal the total number of oranges per box.

Our equation is $15\div5=o$

3=o

5x3

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Example Question #504 : How To Divide

I have oranges and boxes. I am going to put the same number of oranges in each box. How many oranges will be in each box?

Possible Answers:

Correct answer:

Explanation:

Looking at the picture below, we have a total of oranges and boxes. Each box has oranges in it.

Because we are splitting the oranges up into equal groups, this is a division problem.

Let's let equal the total number of oranges per box.

Our equation is $12\div4=o$

3=o

4x3

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Example Question #511 : How To Divide

I have oranges and boxes. I am going to put the same number of oranges in each box. How many oranges will be in each box?

Possible Answers:

Correct answer:

Explanation:

Looking at the picture below, we have a total of oranges and boxes. Each box has oranges in it.

Because we are splitting the oranges up into equal groups, this is a division problem.

Let's let equal the total number of oranges per box.

Our equation is $9\div3=o$

3=o

3x3

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : Numbers and Operations

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #31 : Solve Multistep Word Problems Using The Four Operations: Ccss.Math.Content.4.Oa.A.3

Example Question #3552 : Operations

Example Question #11 : Multiplying And Dividing Within 100

Example Question #12 : Multiplying And Dividing Within 100

Example Question #41 : The Number System

Example Question #501 : How To Divide

Example Question #502 : How To Divide

Example Question #503 : How To Divide

Example Question #504 : How To Divide

Example Question #511 : How To Divide

All SSAT Elementary Level Math Resources

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