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SSAT Elementary Level Math : SSAT Elementary Level Quantitative (Math)

Study concepts, example questions & explanations for SSAT Elementary Level Math

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #16 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}20\\ \times\ 8\end{array}}{ \ \ \ \space}$

Possible Answers:

120

160

140

180

190

Correct answer:

160

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$8\times0=0$

$8\times2=16$

$\frac{\begin{array}[b]{r}20\\ \times\ 8\end{array}}{ \ \space160}$

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Example Question #17 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}90\\ \times\ 7\end{array}}{ \ \ \ \space}$

Possible Answers:

640

650

670

630

660

Correct answer:

630

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$7\times0=0$

$7\times9=63$

$\frac{\begin{array}[b]{r}90\\ \times\ 7\end{array}}{ \ \space630}$

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Example Question #18 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}30\\ \times\ 1\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$1\times0=0$

$1\times3=3$

$\frac{\begin{array}[b]{r}30\\ \times\ 1\end{array}}{ \ \ \space30}$

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Example Question #116 : Number & Operations In Base Ten

$\frac{\begin{array}[b]{r}40\\ \times\ 2\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$2\times0=0$

$2\times4=8$

$\frac{\begin{array}[b]{r}40\\ \times\ 2\end{array}}{ \ \ \ \space80}$

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Example Question #117 : Number & Operations In Base Ten

$\frac{\begin{array}[b]{r}50\\ \times\ 3\end{array}}{ \ \ \ \space}$

Possible Answers:

160

170

190

180

150

Correct answer:

150

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$3\times0=0$

$3\times5=15$

$\frac{\begin{array}[b]{r}50\\ \times\ 3\end{array}}{ \ \space150}$

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Example Question #21 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}60\\ \times\ 4\end{array}}{ \ \ \ \space}$

Possible Answers:

210

220

240

200

230

Correct answer:

240

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$4\times0=0$

$4\times6=24$

$\frac{\begin{array}[b]{r}60\\ \times\ 4\end{array}}{ \ \space240}$

Report an Error

Example Question #22 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}70\\ \times\ 5\end{array}}{ \ \ \ \space}$

Possible Answers:

400

420

410

350

300

Correct answer:

350

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$5\times0=0$

$5\times7=35$

$\frac{\begin{array}[b]{r}70\\ \times\ 5\end{array}}{ \ \space350}$

Report an Error

Example Question #23 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

$\frac{\begin{array}[b]{r}80\\ \times\ 6\end{array}}{ \ \ \ \space}$

Possible Answers:

440

460

470

450

480

Correct answer:

480

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$6\times0=0$

$6\times8=48$

$\frac{\begin{array}[b]{r}80\\ \times\ 6\end{array}}{ \ \space480}$

Report an Error

Example Question #2891 : Operations

$\frac{\begin{array}[b]{r}10\\ \times\ 7\end{array}}{ \ \ \ \space}$

Possible Answers:

Correct answer:

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$7\times0=0$

$7\times1=7$

$\frac{\begin{array}[b]{r}10\\ \times\ 7\end{array}}{ \ \ \space70}$

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Example Question #3110 : Ssat Elementary Level Quantitative (Math)

$\frac{\begin{array}[b]{r}30\\ \times\ 8\end{array}}{ \ \ \ \space}$

Possible Answers:

240

260

270

280

250

Correct answer:

240

Explanation:

To solve this problem, we multiply by the ones position and the tens position.

$8\times0=0$

$8\times3=24$

$\frac{\begin{array}[b]{r}30\\ \times\ 8\end{array}}{ \ \space240}$

Report an Error

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All SSAT Elementary Level Math Resources

12 Diagnostic Tests 526 Practice Tests Question of the Day Flashcards Learn by Concept

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SSAT Elementary Level Math : SSAT Elementary Level Quantitative (Math)

Study concepts, example questions & explanations for SSAT Elementary Level Math

All SSAT Elementary Level Math Resources

Example Questions

Example Question #16 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #17 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #18 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #116 : Number & Operations In Base Ten

Example Question #117 : Number & Operations In Base Ten

Example Question #21 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #22 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #23 : Multiply One Digit Numbers By Multiples Of 10: Ccss.Math.Content.3.Nbt.A.3

Example Question #2891 : Operations

Example Question #3110 : Ssat Elementary Level Quantitative (Math)

All SSAT Elementary Level Math Resources

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