The length of the rectangle would be: \(\displaystyle 3\times 3=9\ m\)

The area of a rectangle is found by multiplying the width by the length.

\(\displaystyle A=w\times l\)

We know that the width is 4 feet and the the length must be twice the width. Multiply the width by 2 to find the length.

\(\displaystyle l=2\times4=8\)

Multiply the length and width to find the area.

\(\displaystyle 4\times8=32\)

The cubic feet of an area is found by multiping the length times the width times the height. Given that the length is six feet, the width is two feet, and that the height is two feet, the total cubic area would be found using this equation:

\(\displaystyle length\cdot width \cdot heighth\)

Here is the equation with the appropriate numbers plugged in:

\(\displaystyle 6\cdot 2\cdot 2 = 24\)

Therefore, 24 cubic feet is the correct answer. 

The area of a rectangle if found by multiplying the length times the width. Here, we know that Lisa's blanket is half the area of Jessica's blanket. Since Jessica's blanket is 12 square feet, that means that Lisa's blanket must be 6 square feet. 

The only length and width values that give us 6 square feet when multiplied by one another are 3 feet by 2 feet. This is therefore the correct answer. 

The large rectangle has length 80 and width 40, and, consequently, area

\(\displaystyle 80 \times 40 = 3,200\).

The white region is a rectangle with length 30 and width 20, and, consequently, area 

\(\displaystyle 30 \times 20 = 600\).

The red region, therefore, has area \(\displaystyle 3,200 - 600 = 2,600\). 

The red region is 

\(\displaystyle \frac{2,600}{3,200} \times 100 = 81 \frac{1}{4} \%\)

of the large rectangle.

This is not one of the choices.

The large rectangle has length 80 and width 40, and, consequently, area

\(\displaystyle 80 \times 40 = 3,200\).

The white region is a rectangle with length 30 and width 20, and, consequently, area 

\(\displaystyle 30 \times 20 = 600\).

The red region, therefore, has area \(\displaystyle 3,200 - 600 = 2,600\). 

The ratio of the area of the red region to that of the white region is 

\(\displaystyle \frac{2,600}{600} = \frac{2,800 \div 200}{600\div 200 }= \frac{13}{3}\)

That is, 13 to 3.

The tarp needed to cover this pool must be, at minimum, the product of its length and width, or

\(\displaystyle 24 \times 15 = 360\) square meters. 

The manager will need to buy a number of square yards of tarp equal to the next highest multiple of one hundred, which is 400 square meters.

In a square, each angle is 90 degrees.

\(\displaystyle A=B=C=D=90^o\)

We can plug in 90 for each variable and find the sum.

\(\displaystyle A+B+C=90^o+90^o+90^o=270^o\)

The bottom of the swimming pool has area 

\(\displaystyle 50 \times 35 = 1,750\) square feet.

There are two sides whose area is 

\(\displaystyle 50 \times 6 = 300\) square feet,

and two sides whose area is 

\(\displaystyle 35 \times 6 = 210\) square feet.

Add the areas:

\(\displaystyle 1,750 + 300 + 300 + 210 +210=2,770\) square feet.

Given that there are 360 degrees in a quadrilateral, 

\(\displaystyle b+2b+3b+3b=360\)

\(\displaystyle 9b=360\)

\(\displaystyle b=40\)