All SSAT Upper Level Math Resources
Example Questions
Example Question #3 : How To Graph A Point
What are the coordinates for point L?
Find the x-coordinate by going right on the horizontal x-axis until you come across the line that is directly above the point. The x-coordinate is .
Now, continue down until you reach the point and look across to the vertical y-axis. The y-coordinate is .
are the coordinates for point L.
Example Question #331 : Coordinate Geometry
What are the coordinates for point M?
Find the x-coordinate by going right on the horizontal x-axis until you come across the line that is directly under the point. The x-coordinate is .
Now, continue up until you reach the point and look across to the vertical y-axis. The y-coordinate is .
are the coordinates for point M.
Example Question #862 : Act Math
What are the coordinates for point K?
Find the x-coordinate by going left on the horizontal x-axis until you come across the line that is above the point. The x-coordinate is .
Now, continue down until you reach the point and look across to the vertical y-axis. The y-coordinate is .
are the coordinates for point K.
Example Question #6 : How To Graph A Line
Refer to the above red line. A line is drawn perpendicular to that line, and with the same -intercept. Give the equation of that line in slope-intercept form.
First, we need to find the slope of the above line.
The slope of a line. given two points can be calculated using the slope formula
Set :
The slope of a line perpendicular to it has as its slope the opposite of the reciprocal of 2, which would be . Since we want this line to have the same
-intercept as the first line, which is the point
, we can substitute
and
in the slope-intercept form:
Example Question #257 : Algebra
Refer to the above diagram. If the red line passes through the point , what is the value of
?
One way to answer this is to first find the equation of the line.
The slope of a line. given two points can be calculated using the slope formula
Set :
The line has slope 3 and -intercept
, so we can substitute
in the slope-intercept form:
Now substitute 4 for and
for
and solve for
:
Example Question #611 : Ssat Upper Level Quantitative (Math)
Multiply:
FOIL the product out:
Example Question #612 : Ssat Upper Level Quantitative (Math)
Simplify:
Use the square of a binomial pattern to multiply this:
Example Question #72 : Graphing
Multiply:
This is a product of an imaginary number and its complex conjugate, so it can be evaluated using this formula:
Example Question #613 : Ssat Upper Level Quantitative (Math)
Multiply:
This is a product of an imaginary number and its complex conjugate, so it can be evaluated using this formula:
Example Question #5 : How To Graph Complex Numbers
Define an operation as follows:
For all complex numbers ,
Evaluate
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All SSAT Upper Level Math Resources
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